Answer:
(-15)-(-3) = -12
(1-7)+(+5) = -1
(+5) x ( +6 ) = 30x
(+18 ) + ( +6) 24
(9)+( 8 ) = 17
(+10)-(+1) = 9
( +4 ) x ( 3 ) = 12x
( 12 ) + ( +4 ) = 16
(+6) + (6) 12
(+11)-(7) = 4
(-8) x ( +2 ) = -16x
(+15) + ( 3 ) = 18
(*12 ) + ( 4) = 4
(8) - ( +2) = 6
(-7) x ( -5 ) = 35x
HOPE THIS HELPS : D I TOOK A LOT OF WORK ON THIS <3
Answer:
The domain of a relation is the set of all the x-terms of the relation.
If an x-term appears twice in a relation, only list in once in the domain
The x-values for those three ordered pairs are 2, -2, and -2. For the first ordered pair, you move two positive units along the x-axis, and then along the y-axis to -11. For the second ordered pair, you first move two negative units on the x-axis to -2, and then 11 positive units on the y-axis
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as there are lots of missing details in the question. To do this, I will make assumptions
See attachment for question illustration where
the height of the second floor
the distance where the base of the ladder is placed
the length of the ladder
So, we are to solve for x.
Using Pythagoras theorem, we have:
![l^2 = x^2 + y^2](https://tex.z-dn.net/?f=l%5E2%20%3D%20x%5E2%20%2B%20y%5E2)
Make
the subject
![x^2 = l^2 - y^2](https://tex.z-dn.net/?f=x%5E2%20%3D%20l%5E2%20-%20y%5E2)
Take square roots of both sides
![x = \sqrt{l^2 - y^2](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7Bl%5E2%20-%20y%5E2)
The above is the expression to calculate the base length of the ladder.
Assume
![y=50; l = 30](https://tex.z-dn.net/?f=y%3D50%3B%20l%20%3D%2030)
So, we have:
![x = \sqrt{50^2 - 30^2](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B50%5E2%20-%2030%5E2)
![x = \sqrt{2500 - 900](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B2500%20-%20900)
![x = \sqrt{1600](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B1600)
![x =40](https://tex.z-dn.net/?f=x%20%3D40)