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3 years ago

2(4-3x)=2(2x-1) what is the answer

Mathematics

2 answers:

Margarita [4]3 years ago

8 0

The answer would be x is less than or equal to 1

KiRa [710]3 years ago

4 0

Divide both sides of the equation by 2

4 - 3x = 2x - 1

-3x - 2x = -1 - 4

-5x = -5

Divide both sides of the equation by -5

x = 1

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Naya [18.7K]

Answer:

B x = sqrt(48)

Step-by-step explanation:

Half of the bottom side measures 4.

4^2 + x^2 = 8^2

16 + x^2 = 64

x^2 = 48

x = sqrt(48)

Answer: B x = sqrt(48)

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3 years ago

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2 years ago

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2 years ago

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2 years ago

Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

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2 years ago