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3 years ago

6

2(4-3x)=2(2x-1) what is the answer

2 answers:

Margarita [4]3 years ago

8 0

The answer would be x is less than or equal to 1

KiRa [710]3 years ago

4 0

Divide both sides of the equation by 2

4 - 3x = 2x - 1

-3x - 2x = -1 - 4

-5x = -5

Divide both sides of the equation by -5

x = 1

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Solve: 3 ln x = ln 216

BaLLatris [955]

$3\ln x=\ln 216\\ \ln x^3 =\ln 216\\ x^3=216\\ x=6$

3 0

3 years ago

Read 2 more answers

The sum of ruqiyo’s age and Mohammed’s age is 117. Five times ruqiyo’s age is 9 more than 3 times mohammed’s age. How old is eac

Bess [88]

Answer:

45 and 72

Step-by-step explanation:

Let the ages be r and m

<u>We have:</u>

r + m = 117
5r = 9 + 3m

<u>Substitute m in the second equation and solve for r:</u>

m = 117 - r
5r = 9 + 3( 117 - r)
5r = 9 + 351 - 3r
5r + 3r = 360
8r = 360
r = 360/8
r = 45

<u>Then m is</u>

m = 117 - 45 = 72

3 0

2 years ago

lions [1.4K]

Answer:

b=9,a=12

Step-by-step explanation:

I solved by substitution:

b = 3/4a ---> plug this into the other equation

a + b = 21 is now a + 3/4a = 21

Reduce: 7/4a = 21

a = 12

Now solve for b:

b=3/4a is now b=3/4(12)

b=9

6 0

3 years ago

Read 2 more answers

I cut 65 cm off 2 m of rope how much is left

lesantik [10]

2m = 200cm

200cm-65m= 135cm

:)

4 0

3 years ago

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago