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likoan [24]
3 years ago
9

T is 4 more than the product of 7 and s

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0

Answer:

T = 7s+4

Step-by-step explanation:

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If im making 12 a hour and get a 10% increase how much more im making
Art [367]

Answer:

13.2/hour

Step-by-step explanation:

10% of 12 = 1.2

12+1.2=13.2

4 0
3 years ago
Could -2 be used to rewrite 32
Ostrovityanka [42]

Answer:Look at this list of whole number powers of -2:

(-2)0 = 1

(-2)1 = -2

(-2)2 = 4

(-2)3 = -8

(-2)4 = 16

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Drag each expression to show whether it is equivalent to
Kazeer [188]

Answer:

We need to find which expressions are equivalent to 6(c+6), 6c+6 or neither.

6c+12: We extract the greatest common factor which is 6. Remember, when we extract a GCM, we divide each term by it.

6c+12=+(c+2)

Therefore, this expression is equivalent to neither of the given expressions.

2(3c+3): We just need to apply the distributive property.

2(3c+3)=6c+6

Therefore, this expression is equivalen to 6c+6.

We use the same process to the other expressions.

(6c)+(6\times 6)=6c+36=6(c+6)

3c+6+3c=6c+6

6c+36=6(c+6)

(6+c)+(6+6)=c+18, equivalent to neither.

7 0
2 years ago
Peter spent 3/5 of his money and was left with $60. 1. How much money did he have at first2. Express what he remained with as a
german

60 / 2 = 30

30 * 5 = 150

he had $150 at first

60, the amount he was left with was 2/5 or 40% of his original amount

4 0
2 years ago
Carol is solving the inequality 3 have?<br> There are infinitely many solutions.<br> There are only two solutions.<br> There is
schepotkina [342]

Answer:

There are infinitely many solutions

Step-by-step explanation:

Firstly, I need to change f to x as the system won’t accept the word f

Let’s take a look at the question;

3 is less than x

The domain of our answer lies in the the range of values where we have numbers that are greater than 3

This means we can rewrite our inequality as x is greater than 3

Now, simply because we have an infinite amount of numbers which are greater than 3 of which x can take any of the values, we can conclude that the number of values we have for x are infinite and does not end

This makes us have infinitely many solutions for the value of x

6 0
3 years ago
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