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3 years ago

Please help! answer correct for 10 points and brainliest.

Mathematics

2 answers:

labwork [276]3 years ago

7 0

Yea it’s 14 the first one is right

babymother [125]3 years ago

3 0

Answer:

14 square cm Should be the answer, plz do correct me if im wrong!!

Step-by-step explanation:

The right side which is triangle is 2x3 is 6 but because there is only half 6/2

it is 3!

Th middle portion which is square is 2 to the 4th power or 2x2x2x2 or just 2x4(2^4)!! Which is 8!

Finally the last triangle is the same as the first 3

8+6(the to triangles 3+3)=14

Mark brainliest plz, it was nice helping you if im wrong plz tell me immdiately i dont want to cause any problems good day ;)

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Pls help asap!!!

Westkost [7]

Answer:

Step-by-step explanation:

Let x be the random variable. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

From the information given,

µ = 474

σ = 32

x = 514

The probability of being below 514 is expressed as P(x < 514)

For x = 514,

z = (514 - 474)/32 = 1.25

Looking at the normal distribution table, the probability value corresponding to area below the z score is 0.89

Therefore,

P(x < 514) = 0.89

5 0

3 years ago

Need pleas ok need today

Vsevolod [243]

Answer:

Step-by-step explanation:

You need to simply add all the given numbers together and enter the missing number that'll make the total 0. So:

-75 + (-25) = -100

-100 + 10 = -90

-90 + <u>90</u> = 0

Thus, adding a 90 in the empty box will make it 0.

5 0

2 years ago

Read 2 more answers

I Need help please I don’t understand this

Otrada [13]

Remember that parentheses come first. Follow PEMDAS

4 0

2 years ago

Which statement is true? A. ABD DBC by SSS B. ABD DBC by SAS C. ABE DBC by SAS D. ABE CBD by SSS

Bumek [7]

Answer:

D. ABE =CBD by SSS.

Step-by-step explanation:

Given that AB = BD and BE = BC, the lengths of AE and CD are equal to each other. Hence, triangles ABE and BCD are congruent by SSS Theorem. The answer is D.

6 0

3 years ago

You are given the following equation.

saul85 [17]

Answer:

Step-by-step explanation:

Given the equation 4x²+ 49y² = 196

a) Differentiating implicitly with respect to y, we have;

$8x + 98y\frac{dy}{dx} = 0\\98y\frac{dy}{dx} = -8x\\49y\frac{dy}{dx} = -4x\\\frac{dy}{dx} = \frac{-4x}{49y}$

b) To solve the equation explicitly for y and differentiate to get dy/dx in terms of x,

First let is make y the subject of the formula from the equation;

If 4x²+ 49y² = 196

49y² = 196 - 4x²

$y^{2} = \frac{196}{49} - \frac{4x^{2} }{49} \\y = \sqrt{\frac{196}{49} - \frac{4x^{2} }{49} \\} \\$

Differentiating y with respect to x using the chain rule;

Let $u= \frac{196}{49} - \frac{4x^{2} }{49}$

$y = \sqrt{u} \\y =u^{1/2} \\$

$\frac{dy}{dx} = \frac{dy}{du} * \frac{du}{dx}$

$\frac{dy}{du} = \frac{1}{2}u^{-1/2} \\$

$\frac{du}{dx} = 0 - \frac{8x}{49} \\\frac{du}{dx} =\frac{-8x}{49} \\\frac{dy}{dx} = \frac{1}{2} ( \frac{196}{49} - \frac{4x^{2} }{49})^{-1/2} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} ( \frac{196-4x^{2} }{49})^{-1/2} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} ( \sqrt{ \frac{49}{196-4x^{2} })} * \frac{-8x}{49}\\\frac{dy}{dx} = \frac{1}{2} *{ \frac{7}\sqrt {196-4x^{2} }} * \frac{-8x}{49}\\$

$\frac{dy}{dx} = \frac{-4x}{7\sqrt{196-4x^{2} } }$

c) From the solution of the implicit differentiation in (a)

$\frac{dy}{dx} = \frac{-4x}{49y}$

Substituting $y = \sqrt{\frac{196}{49} - \frac{4x^{2} }{49} \\$ into the equation to confirm the answer of (b) can be shown as follows

$\frac{dy}{dx} = \frac{-4x}{49\sqrt{\frac{196-4x^{2} }{49} } }\\\frac{dy}{dx} = \frac{-4x}{49\sqrt{196-4x^{2}}/7} }\\\\\frac{dy}{dx} = \frac{-4x}{7\sqrt{196-4x^{2}}}$

This shows that the answer in a and b are consistent.

6 0

3 years ago