To answer the question, let x be the cost of each hamburger, y be the cost of each medium fries, and z be the cost of each medium drink. The equations that are described in the problem are,
(Miller ) 4x + 3y = 18.69
(James) x + 2y + z = 8.66
(Steven) 2x + y + z = 10.27
Solving simultaneously for the values of the variables give x = 3.36, y = 1.75, and z = 1.8.
Thus, each hamburger costs $3.36. Each medium fries cost $1.75, and each drink costs $1.8.
Answer:
$500
Step-by-step explanation:
We can find the original price of the camera through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities.
<u>Second Discount</u>
20% off means we paid 80%. We know we paid $328 of some price.
I can now cross-multiply by multiplying numerator and denominator from each ratio.
I now solve for y by dividing by 80.
The price after the first discount was $410.
<u>First Discount</u>
We will repeat the steps above with $410. 18% off means we paid 82%.
I can now cross-multiply by multiplying numerator and denominator from each ratio.
I now solve for y by dividing by 82.
The original price was $500.
Answer: B. $430.80
Step-by-step explanation:
Given : Last year Baron Enterprises had $800 million of sales.
It had $270 million of fixed assets that were used at 65% (=0.65) of capacity last year.
Now, the used asset =
million
Now, Baron Enterprises had $800 million of sales in $175.5 million of assets , if we use all of $270 million of fixed assets , then the sales will be :-

Now, the increase in Baron's sales before it is required to increase its fixed assets = 
Hence, the increase in Baron's ( in million ) sales before it is required to increase its fixed assets = $430.80
Answer:
11/2
Step-by-step explanation:
6x−7=26
Step 1: Add 7 to both sides.
6x−7+7=26+7
6x=33
Step 2: Divide both sides by 6.
x= 11/2
Answer:
<h3>
9, 11, 13, 15</h3>
Step-by-step explanation:
{k - some integer}
2k+1 - the first odd integer (the least)
5(2k+1) - five times the least
5(2k+1)+3 -<u> three more than five times the least</u>
2k+1+2 = 2k+3 - the odd integer consecutive to 2k+1
2k+3+2 = 2k+5 - the next odd consecutive integer (third)
2k+5+2 = 2k+7 - the last odd consecutive integer (fourth)
2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>
2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3
8k + 16 = 10k + 5 + 3
- 10k -10k
-2k + 16 = 8
-16 - 16
-2k = -8
÷(-2) ÷(-2)
k = 4
2k+1 = 2•4+1 = 9
2k+3 = 2•4+3 = 11
2k+5 = 2•4+5 = 13
2k+7 = 2•4+7 = 15
Check: 9+11+13+15 = 48; 48-3 = 45; 45:5 = 9 = 2k+1