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3 years ago

Write an equation of the line that passes through (2,-3) and is perpendicular to the line y=-2x-3

Mathematics

1 answer:

Alina [70]3 years ago

3 0

Answer:

y = 1/2 x - 4

Step-by-step explanation:

slope of perpendicular line is 1/2

y +3 = 1/2 (x -2)

y + 3 = 1/2x - 1

y = 1/2x - 4

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What value is equivalent to 5³ – 2 • 3 – (7² + 50)?

Vikentia [17]

Answer: -20

Read more at Answer.Ya.Guru – https://answer-ya.com/questions/5043911-5-2-3-7-50.html

Step-by-step explanation: PEMDAS use this ok first you do 7x7 to equal 49 then add 50 to equal 99. then do 5x5x5 to equal 125. the parentheses are gone and the 5x5x5 is gone now the problem is 125-2x3-99. to finish you multiply 2x3 to equal 6 now 125-6-99=20 answer-20

Read more at Answer.Ya.Guru – https://answer-ya.com/questions/5043911-5-2-3-7-50.html

5 0

2 years ago

The length of the room is two times it's breadth and 5 times it's height. if the volume of the room is 100 m³, what is the cost

elixir [45]

Answer:

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4 0

3 years ago

Una poblacion es atacada por una epidemia de gripe sea N(t)= numero de personas enfermas al tiempo t. En dias la epidemia inicio

Lisa [10]

Answer:

Habrán 10175 enfermos a los 15 dias.

Step-by-step explanation:

La tasa de cambio de la población enferma por la epidemia de gripe es:

$N'(t)=120t-3t^2$

Donde t es el tiempo en dias, y se sabe que la epidemia inició en N(0)=50.

Para encontrar la función original que describe el comportamiento de la epidemia, debemos integrar la función:

$N(t)=\int N'(t)dt$

$N(t)=\int (120t-3t^2)dt$

Integrando:

$\displaystyle N(t)=120\frac{t^2}{2}-3\frac{t^3}{3}+C$

Simplificando:

$\displaystyle N(t)=60t^2-t^3+C$

Para determinar el valor de C, usamos la condición inicial N(0)=50:

$\displaystyle 50=60(0)^2-(0)^3+C$

Se tiene que C=50, y la función queda determinada como:

$\displaystyle N(t)=60t^2-t^3+50$

b) El número de enfermos a los t=15 dias se determina substituyendo el valor en la función original:

$\displaystyle N(15)=60(15)^2-(15)^3+50$

Calculando:

$N(15)=13500-3375+50=10175$

Habrán 10175 enfermos a los 15 dias.

8 0

3 years ago

After years of maintaining a steady population of 32,000, the population of a town begins to grow exponentially. After 1 year an

elixir [45]

Answer:

The equation used to predict the number of people living in the town after x years is y = 32,000 (1.08)x

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

Initial population: 32,000

Growth per year: 8%

Years: x

So, to obtain "y" (the number of people living in the town after x years), we have to multiply the initial population by 1+ 0.08 (the growth rate is 8%/100=0.08 and the original value) and the number of years (x).

Mathematically speaking:

y = 32,000 (1+0.08) x

y= 32,000 (1.08) x

The equation used to predict the number of people living in the town after x years is y = 32,000 (1.08)x

6 0

3 years ago

Read 2 more answers

What is the circumference of a circle with a diameter of 10 in?

Kipish [7]

The answer is 31.42 since the radius is five and then you multiply it times squared and then times 3.14

3 0

3 years ago