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FromTheMoon [43]
3 years ago
6

Will’s Whitewater Rafting sold 3 acres of land used in the business. The sales price was $6,000 and the adjusted basis of the la

nd was $4,200. Will receives a down payment of $4,000 at the time of sale and the remaining $2,000 early next year. The realized gain on the sale is $___. Will’s recognized gain for the current year is $_____ and the gain recognized next year will be $_____.
a. 1,800;
b. 1,200 ($1,800/$6,000 = 30%; $4,000 x .30 = $1,200);
c. 600 (30% x $2,000 = $600)
Business
1 answer:
Advocard [28]3 years ago
3 0

Answer:a. 1,800;

b. 1,200 ($1,800/$6,000 = 30%; $4,000 x .30 = $1,200);

c. 600 (30% x $2,000 = $600)

Explanation:

In tax accounting, adjusted basis refers to the original cost, or the net cost of an asset, after adjusting various tax-related items normally reduced by depreciation deductions.

Given:

Selling Price(S.P) = $6,000

Adjusted Basis (A.B) = $4200

The gain realized from the sale of the land would be:

= S.P - A.B = $(6,000-4200)= $1,800

Now, we calculate the percentage profit on gain realized to enable ease of gain calculation for fragmented payments.

The percentage gain (P.G) is:

(S.P-A.B)/S.P * 100 = (6,000-1,800)/6000 * 100

P.G = (1,800/6,000) * 100 = 30%

Therefore we say that:

Recognized Gain on current year = Amount paid * P.G = $(4,000*0.3) = $1,200

And

Recognized Gain next year = Amount paid * P.G = $(2,000 * 0.3) = $600

Note: P.G is percentage gain.

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Answer:

a) Qs = 50 + 20p - 7ps

= 50 + 20p - 7×(2)

= 50 + 20p - 14

= 36 + 20p

At equilibrium, Q_{d} = Q_{s}

So, 150 - 10p + 5p_{b} = 36 + 20p

So, 20p + 10p = 30p

= 150 - 36 + 5p_{b}

= 114 + 5p_{b}

So, p = (114/30) + (5/30)p_{b}

= 3.8 + 0.17p_{b}

Thus, p_{e} = 3.8 + 0.17p_{b}

Q = 36 + 20p

= 36 + 20(3.8 + 0.17p_{b})

= 36 + 76 + 3.4p_{b}

= 112 + 3.4p_{b}

Thus, Q_{e} = 112 + 3.4p_{b}

b) p_{e} = 3.8 + 0.17p_{b}

= 3.8 + 0.17×(5)

= 3.8 + .85

= 4.65

Q_{e} = 112 + 3.4_{b}

= 112 + 3.4(5)

= 112 + 17

= 129

c) Qd = 150 - 10p + 5pb = 150 - 10(2.5) + 5(5) = 150 - 25 + 25 = 150

Qs = 36 + 20p = 36 + 20(2.5) = 36 + 50 = 86

Thus, there is excess demand as Q_{d} > Q_{s}

d) New Q_{d}= 180 - 10p + 5p_{b}

= 180 - 10p + 5×(5)

= 180 - 10p + 25

= 205 - 10p

Now, new Q_{d} = Q_{s} gives,

205 - 10p = 36 + 20p

So, 20p + 10p = 205 - 36

So, 30p = 169

So, p = 169÷30

So, p_{e} = 5.63

Q = 205 - 10p = 205 - 10×(5.63) = 205 - 56.3 = 148.7

So, Q_{e} = 148.7

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The operational design of an illicit drug business can be divided into four stages of production and distribution: cultivation,
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Retail distribution

The illegal drug business or trade primarily consists of the cultivation, manufacture, distribution and sales of prohibited drugs.

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Answer:

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Answer:

D.  C

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