Answer:
True
Step-by-step explanation:
The definition of the function is a relation with exactly one x for each y. x is the domain, and y is the range, so all functions have a domain and a range.
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.
Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.
sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
Answer:
(x+3)²-11=0
Step-by-step explanation:
0=9(x2+6x)-18
0= 9x² +54x-18
0= 9( x²+6x-2) taking 9 common
0= x² +6x-2 (breaking the mid term to find the second element of the square
0 = (x)² +2(x)(3) +(3)² -2 -9 adding and subtracting the second element
0= (x+3)² -11 summing up
Answer:
Square Root of 162 ~ 12.727
Step-by-step explanation:
Simply do the Pythagorean Theorem!
a^2 + b^2 = c^2
This case we're solving for the long side which is the hypothenuse.
9^2+9^2= c^
81+81=c^
162=c^
Square root of 162
Which is 12.727
Answer:
the answer is 2 + i.
Step-by-step explanation:
Let the square root of 3 + 4i be x + iy.
So (x + iy) (x +iy) = 3 +4i
=> x^2 + xyi + xyi + i^2*y^2 = 3 + 4i
=> x^2 – y^2 + 2xyi = 3 + 4i
Equate the real and complex terms
=> x^2 - y^2 = 3 and 2xy = 4
2xy = 4
=> xy = 2
=> x = 2/y
Substitute in
=> x^2 - y^2 = 3
=> 4/y^2 - y^2 = 3
=> 4 – y^4 = 3y^2
=> y^4 + 3y^2 – 4 = 0
=> y^4 + 4y^2 – y^2 – 4 =0
=> y^2(y^2 + 4) – 1(y^2 + 4) =0
=> (y^2 – 1) (y^2 + 4) =0
Therefore y^2 = 1, we ignore y^2 = -4 as it gives complex values of y.
Therefore y = 1 and x = 2/1 = 2
The required square root of 3 + 4i is 2 + i.
