That's of course the 30/60/90 right triangle.
If you need to see the algebra, the acute angles in a right triangle are complementary, adding to 90 degrees:
x + 2x = 90
3x = 90
x = 30
Answer:
there is 16.08 foot high does the ladder reach on the building
Step-by-step explanation:
The computation of the high does the ladder reach on the building is shown below:
Given that
length of the ladder = 17 ft
angle -between the ground and the ladder = 75 degrees
Based on the above information
Here we used the trig-ratio to calculate the same

0.946 × 17 = h
The height is 16.08 foot
Hence, there is 16.08 foot high does the ladder reach on the building
Answer:
B) x < 9 or x > 23
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I'm so sorry if I'm not correct, but that's the only answer that makes any sense to the sentence.
The dimensions of the rectangular( length and width) are 14m and 15m.
Here we have to find the dimension of the length and width.
Data given:
Fencing = 58m
Area = 210 m²
Let us assume the length be x
By this, we get the width as:
width = 58 - 2x / 2
= 29-x
As the area is 210 m²
The formula to find the area of the rectangular is:
Area = length ×width
210 = x ( 29 -x)
x² - 29 x + 210 = 0
Formula to find the value of x from the quadratic equation:
x = -b ±
For the general equation ax² + bx + c =0
As the equation is:
x² - 29x + 210 = 0
a = -1
b = -29
c = -210
So,
x = 29 ±
/ 2(-1)
= 29± 1/-2
= 14, 15
29 - x = 15, 14 (for the value of x = 14 and 15 respectively)
Therefore the dimensions are 14m and 15m.
To know more about the rectangular refer to the link given below:
brainly.com/question/25292087
#SPJ4
Answer:
I think it is 4.52 × 10^-4