Help poor mi............

Mathematics

2 answers:

lions [1.4K]3 years ago

6 0

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Firlakuza [10]3 years ago

5 0

The chosen topic is not meant for use with this type of problem. Try the examples below.

$cot (3x),x=\frac{2\pi }{3}$

$cot ( \frac{x}{2}, x=\frac{\pi }{2}$

$cos (x), x = \frac{x}{2}$

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Use the Remainder Theorem to find the remainder of (x3 – 2x2 + 3x – 1) ÷ (x + 2).

LUCKY_DIMON [66]

Zero of divisor (x+2) is -2

Now putting the value of x as -2,
${( - 2)}^{3} - 2 {( - 2)}^{2} + 3( - 2) - 1 \\ - 8 - 8 - 6 - 1 \\ - 23$

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3 years ago

What is the area?????

Pani-rosa [81]

Answer:

The answer is 48 square inches

Step-by-step explanation:

6x8=48

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3 years ago

Last month, a cafe had 3200 customers. 600 of them ordered gluten-free meals. What percentage of the customers ordered gluten-fr

Alexus [3.1K]

18.75%

Step-by-step explanation:

600÷3200=0.1875

0.1875=18.75%

6 0

3 years ago

Read 2 more answers

Find the maximum rate of change of f at the given point and the direction in which it occurs. f(p, q) = 8qe−p + 4pe−q, (0, 0) ma

Pachacha [2.7K]

Answer:

Step-by-step explanation:

$Given \ f (p,q) = 8qe^{-p} + 4pe^{-q} \ where \ P_o(0,0) \\ \text{thus the gradient of f is: } \\ \\ \bigtriangledown f(p,q) = \Big(\dfrac{\partial f}{\partial p}, \dfrac{\partial f}{\partial q} \Big) \\ \\ \dfrac{\partial f}{\partial p} = -8qe^{-p} + 4pe^{-q} \\ \\ \dfrac{\partial f}{\partial p} = 8qe^{-p} - 4pe^{-q} \\ \\ Then: \bigtriangledown f(p.q) = (-4qe^{-p}+ 8qe^{-q}, 4qe^{-p}- 8qe^{-q}) \\ \\ f(0,0) = (-4*(0)e^{-0}+ 8*(0)e^{-(0)}, 4*(0)e^{-(0)}- 8*(0)e^{-(0)}) \\ \\ = (0+8,4-0) = (8.4)$