Answer:
42.42in³
Step-by-step explanation:
This problem bothers on the mensuration of solid shapes, a cone
Step one
We know that the volume of a cone is
V= 1/3πr²h
Given data
Diameter d= 6 inches
Radius r= diameter/2= 6/2= 3 inches
Height h = 4.5 inches
Step two
Substituting our given data we have
Volume = 1/3*3.142*3²*4.5
V= 1/3*3.142*9*4.5
V= 127.251/3
V= 42.42in³
<h3>9)</h3><h3>5 planes</h3>
<h3>10)</h3><h3>2 planes</h3>
<h3>11)</h3><h3>BCED</h3>
<h3>12)</h3><h3>Yes , they belong to plane (w)</h3>
Answer:
- 3a³ + 5a² - 3a + 7
Step-by-step explanation:
Given
(a³ - 2a + 5) - (4a³ - 5a² + a - 2)
Distribute both parenthesis noting the second is distributed by - 1
= a³ - 2a + 5 - 4a³ + 5a² - a + 2 ← collect like terms
= (a³ - 4a³ ) + 5a² + (- 2a - a) + (5 + 2)
= - 3a³ + 5a² - 3a + 7
Answer:
The total surface area of triangular pyramid is 172 cm squared
Step-by-step explanation:
Triangular pyramid:
- Number of faces 4.
- Number of vertices of a triangular pyramid is 6.
- The volume is
. A= area of the pyramid's base and H= height of the pyramid.
- The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.
Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.
The 3 sides of the triangular pyramid is triangle in shape.
The area of triangle is
.
The lateral surface area of the triangular pyramid is

cm squared
=129 cm squared
The total surface area of triangular pyramid is
=Area of the base + lateral surface area
=(43+129) cm squared
=172 cm squared