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Vsevolod [243]
3 years ago
15

Solve 4(2a-1) = -10(a-5)

Mathematics
2 answers:
densk [106]3 years ago
4 0
Firstly, you've got to expand the brackets, this becomes;
8a-4= -10a+ 50
You've then got to eliminate the -10a and you do this by adding 10a to both sides,
This then becomes 18a-4=50
You've then got to add 4, to eliminate this, which then becomes 18a=54
You've then got to divide both sides by 18, and this becomes 3.
Therefor, a=3
Hope this helps :)
never [62]3 years ago
4 0
8a-4=-10a+50
+10a   +10a \\ 18a-4=50 \\ +4 +4 \\ 18a=54 \\ /18 /18 \\ a=3

Hope this helps :)

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Answer:

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Step-by-step explanation:

we are given a function

\displaystyle \sf h(x) =  \frac{2x - 6}{4 {x}^{2}  + 8}

we would like to simplify it for h(-1)

in order to do so

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\displaystyle \sf h( - 1) =  \frac{2 \cdot - 1- 6}{4 { (- 1)}^{2}  + 8}

by order of PEMDAS

simplify square:

\displaystyle \sf h( - 1) =  \frac{2 \cdot - 1- 6}{4 { ( 1)}^{}  + 8}

simplify multiplication:

\displaystyle \sf h( - 1) =  \frac{ - 2 - 6}{4 { }^{}  + 8}

simplify addition:

\displaystyle \sf h( - 1) =  \frac{ - 2 - 6}{12}

simplify subtraction:

\displaystyle \sf h( - 1) =  \frac{   - 8}{12}

reduce fraction:

\displaystyle  \sf h( - 1) =   - \frac{    2}{3}

5 0
3 years ago
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Hope this helps!

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