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Simora [160]
2 years ago
15

8) A pyramid has a rectangluar base with length 12 km and width of 5 km. If the volume is 200

Mathematics
1 answer:
SashulF [63]2 years ago
6 0

Hi there!

\large\boxed{h = 10km}

We know that the equation for the volume of a pyramid is:

V = 1/3(bh)

We know that:

V = 200 km³

b = 12 × 5 = 60 km²

We can plug these into the equation:

200 = 1/3(60)(h)

Simplify:

200 = 20h

Divide both sides by 20:

200/20 = 20h/20

h = 10 km

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For Part B, you need to square the function from the general equation Ax^2+Bx+C=0. So to do that, we use the equated form of the equation 0=-250n^2+3,250n-9,000 and in order to have a positive value of 250n^2, we divide both sides by -1

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to simplify, we divide it by 250 to get n^2-13n+36=0 or n^2-13n = -36 (this form is easier in order to complete the square, ax^2+bx=c)

in squaring, we need to apply <span><span><span>(<span>b/2</span>)^2 to both sides where our b is -13 so,
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(n-13/2)^2 = 25/4 then to find the value of n, we apply the square root to both sides to obtain n-13/2 = 5/2 and n is 9. This gives us the confirmation from Part A. 

For Part C, since the function is a binomial so the graph is a parabola. The axis of symmetry would be x=5.

</span></span></span>
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3 years ago
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Answer:

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