Answer:
102
Step-by-step explanation:
it's a parallelogram so it's BxH
A = 15x8 = 120
inside rectangle A is LxW
6x3 = 18
subtract the inside from the outside
120-18 = 102
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That's very interesting. I had never thought about it before.
Let's look through all of the ten possible digits in that place,
and see what we can tell:
-- 0:
A number greater than 10 with a 0 in the units place is a multiple of
either 5 or 10, so it's not a prime number.
-- 1:
A number greater than 10 with a 1 in the units place could be
a prime (11, 31 etc.) but it doesn't have to be (21, 51).
-- 2:
A number greater than 10 with a 2 in the units place has 2 as a factor
(it's an even number), so it's not a prime number.
-- 3:
A number greater than 10 with a 3 in the units place could be
a prime (13, 23 etc.) but it doesn't have to be (33, 63) .
-- 4:
A number greater than 10 with a 4 in the units place is an even
number, and has 2 as a factor, so it's not a prime number.
-- 5:
A number greater than 10 with a 5 in the units place is a multiple
of either 5 or 10, so it's not a prime number.
-- 6:
A number greater than 10 with a 6 in the units place is an even
number, and has 2 as a factor, so it's not a prime number.
-- 7:
A number greater than 10 with a 7 in the units place could be
a prime (17, 37 etc.) but it doesn't have to be (27, 57) .
-- 8:
A number greater than 10 with a 8 in the units place is an even
number, and has 2 as a factor, so it's not a prime number.
-- 9:
A number greater than 10 with a 9 in the units place could be
a prime (19, 29 etc.) but it doesn't have to be (39, 69) .
So a number greater than 10 that IS a prime number COULD have
any of the digits 1, 3, 7, or 9 in its units place.
It CAN't have a 0, 2, 4, 5, 6, or 8 .
The only choice that includes all of the possibilities is 'A' .
Perpendicular sides or lines meet at right angles. The conclusion that can be reached is that:
<em>1. all of the rings are perpendicular to that side.</em>
The statements in the question can be listed as:
- <em>Rings in the ladder are parallel</em>
- <em>Top ring is perpendicular to the side of the ladder</em>
<em />
From statements 1 and 2 above, we understand that;
<em>All other rings in the ladder are parallel to the side ring</em>
This means that the relationship between the top ring and the side of the ladder is the same as the relationship between other rings and the side of the ladder
i.e. the side rings are also perpendicular to the side of the ladder
Hence, the conclusion that can be reached is:
<em>1. all of the rings are perpendicular to that side.</em>
Read more about parallel and perpendicular sides at:
brainly.com/question/8607613