In the C programming language, you can't determine the array size from the parameter, so you have to pass it in as an extra parameter. The solution could be:
#include <stdio.h>
void swaparrayends(int arr[], int nrElements)
{
int temp = arr[0];
arr[0] = arr[nrElements - 1];
arr[nrElements - 1] = temp;
}
void main()
{
int i;
int myArray[] = { 1,2,3,4,5 };
int nrElements = sizeof(myArray) / sizeof(myArray[0]);
swaparrayends(myArray, nrElements);
for (i = 0; i < nrElements; i++)
{
printf("%d ", myArray[i]);
}
getchar();
}
In higher languages like C# it becomes much simpler:
static void Main(string[] args)
{
int[] myArray = {1, 2, 3, 4, 5};
swaparrayends(myArray);
foreach (var el in myArray)
{
Console.Write(el + " ");
}
Console.ReadLine();
}
static void swaparrayends(int[] arr)
{
int temp = arr[0];
arr[0] = arr.Last();
arr[arr.Length - 1] = temp;
}
Answer:
on the motherboard inside the computer
Answer:
Explanation:
The following code is written in Java. Both functions traverse the linkedlist, until it reaches the desired index and either returns that value or deletes it. If no value is found the function terminates.
public int GetNth(int index)
{
Node current = head;
int count = 0;
while (current != null)
{
if (count == index)
return current.data;
count++;
current = current.next;
}
assert (false);
return 0;
}
public int removeNth(int index)
{
Node current = head;
int count = 0;
while (current != null)
{
if (count == index)
return current.remove;
count++;
current = current.next;
}
assert (false);
return 0;
}
Answer:
oh sorry i needed points but i have a friend whos user starts with dida
Explanation:
A pressure regulator application on his computer or a station nearbye
