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dedylja [7]
3 years ago
10

Which of the following is equivalent to |X-1|<5?

Mathematics
1 answer:
joja [24]3 years ago
8 0

【>> brainly.com/question/17076084 <<】

, .

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WILL GIVE A BRAINLEST
andreyandreev [35.5K]
Two end points
One direction

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5 0
3 years ago
Joselyn is a manager at a sign-painting company. She has two painters, Allen and Brianne. Allen can complete a large project in
guajiro [1.7K]

Answer:

8.47 Hours

Step-by-step explanation:

Allen can take 16 hours, while 

Brianne can take 18 hours;

Therefore, in 1 hour Allen will complete a fraction of 1/16, while

in 1 hour Brianne will complete a fraction of 1/18

When working together, in 1 hour they will complete a fraction of (1/18+1/16)

=  17/144,

Therefore; to complete the whole project working together, they will take;

144/17 = 8.47 hours


7 0
3 years ago
What is the missing reason in step 3? A 2-column table with 6 rows is shown. Column 1 is labeled Statements with entries measure
Sholpan [36]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
If 6=2x+4y, what is the value of x+2y?
Tamiku [17]

Answer:

3

Step-by-step explanation:

Take 2 as a common then divide by 2

6÷2 =3

6 0
3 years ago
At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening
pav-90 [236]

Answer:

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

p_v =2*P(z>4)=0.0000633  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

\sigma=3.5 represent the population standard deviation

n=49 sample size  

\mu_o =21 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:  

Null hypothesis:\mu = 21  

Alternative hypothesis:\mu \neq 21  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>4)=0.0000633  

Conclusion  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

8 0
3 years ago
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