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bonufazy [111]
3 years ago
12

A map of a town was made using a scale factor of 1 inch =1/2 mile. On the map, Sonja measures that her house is 3 inches away fr

om Sal's house. What is the actual distance between Sonja's house and sal's house?
Mathematics
1 answer:
NikAS [45]3 years ago
3 0

Answer:

1.5 miles

Step-by-step explanation:

According to the scale, we can simply multiply the distance that Sonja measured on the map by the actual mile distance that it states on the scale (1/2 or 0.5) to calculate the actual distance between Sonja's house and Sal's house like so...

3 * 0.5 = 1.5 miles

Therefore, we can see now that there is a total actual distance of 1.5 miles between both of their houses, which is represented as 3 inches on the map.

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Answer:

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A=2i+3j+4k

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Magnitude =\sqrt{3^2 + 1^2+ 7^2} \\\\Magnitude =\sqrt{9+1+49} \\\\Magnitude =\sqrt{59}

Direction of the sum of the vectors:

\widehat{A + B} =\frac{\overrightarrow{A + B}}{Magnitude\: of \:\overrightarrow{A + B}} \\\\\widehat{A + B} =\frac{3i + j + 7k}{\sqrt {59}} \\\\\widehat{A + B} =\frac{3}{\sqrt {59}} i +\frac{1}{\sqrt {59}} j+\frac{7}{\sqrt {59}} k\\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}} \\\\

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