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kenny6666 [7]
3 years ago
12

According to the order of operations, which of the following operations should be completed first in the following expression?

Mathematics
1 answer:
Kamila [148]3 years ago
4 0

Answer:

Step-by-step explanation:

simplify (5-3)

PEMDAS= parentheses- e -MULTIPLY- DIVIDE - ADD- SUBTRACT

2(5-3)2+62

(2*2)2+62

8+62

70

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3/4 divided by 6 and 2/3
Talja [164]
It would be 0.125 for the first answer
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Craig saved $10,950 in a year. He saved $75 more than what he saved the previous
Dmitry [639]

Answer: $10,875

Step 1: Subtract.

10,950 - 75 = 10,875.

Step 2: Add a dollar sign.

$10,875

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I need help with geometry<br> I know its not the first one
alukav5142 [94]

Answer: ASA, C

Step-by-step explanation:

I think it's ASA cuz since the lines indicate they are parallel, then you can find that the two interior angles are also congruent. Since two angles are the same with the side inbetween being the same, it's probably asa.

5 0
3 years ago
Solve 2x + 4 &gt; 16<br><br> A. x &gt; 10<br> B. x &lt; 6<br> C. x &lt; 10<br> D. x &gt; 6
Salsk061 [2.6K]

Hey there! :)

2x + 4 > 16

We're simply just trying to get x onto it's own side, so let's get rid of any numbers on the same side of it.

We can start out by subtracting both sides by 4.

2x + 4 - 4 > 16 - 4

Simplify.

2x > 12

Then, divide both sides by 2.

2x ÷ 2 > 12 ÷ 2

Simplify.

x > 6

Therefore, our answer is D. x > 6

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6 0
3 years ago
CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte
rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt

By definition of absolute value,

|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)

Over this particular integration interval,

• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and

• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5

so you end up splitting the integral at <em>t</em> = <em>π</em> as

\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt

Now compute the distance:

\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5

\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))

\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82

making B the correct answer.

7 0
2 years ago
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