Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula.
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C.
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space.
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.
basically write the triangle in degree language like this is a acute angle because this is a 70* degree angle and talk more
No, -(5/11) is equivalent to -5 all over 11 so -5/11. You cannot change the denominator
Answer:

Step-by-step explanation:
Given a Parabola that intersects the x-axis at x=3 and x=9.
I presume you want to determine the equation of the parabola.
You can use this form:
Given roots of a parabola, the equation of the parabola is derived using the formula:

The equation of the parabola is:

Answer:
Ok so the area of the frame is 18*12 = 216cm^2
Let’s suppose the width of the frame is x
The total area (painting and frame) is (2x+18)(2x+12) and this is equal to 432
4x^2 + 60x + 216 = 432
4x^2 + 60x - 216 = 0
x^2 + 15x - 54 = 0
(x+18)(x-3) = 0
Therefore x = {-18,3}
Since width of the frame has to be positive, the width has to be 3cm Step-
i hope i helped!