Answer:
Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m × 
(as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
= 
Answer:
V = $3.50t + $90.5....
Step-by-step explanation:
V(t) is a function of t that expresses the value in year 2000+t.
We know that the increase is $3.50 times t.
So,
V(t) = $3.50t + c
where c is the constant.
V(15) = $3.50 (15) + c = $143 [t=15 as mentioned in the question]
and therefore
c = $143 - $3.50 (15)
c= $143 - $52.50
c= $90.5
Now we got the value of c. We can write the equation as
V = $3.50t + $90.5....
Red- 3
yellow- 4
green- 2
blue- 5
= 14 all together
green- 2/14, 1/7, or 14%
blue- 5/14, or 36%
I don't know what you mean by eat it
To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that
and the exponent
are divisible by index
. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is: 
What are we multiplying exactly?
