The shaded octagon is transformed to the unshaded octagon in the coordinate plane below.

Colin has several bottles of water. Each bottle of water holds 3 cups. During the day, he drinks 7 cups of water. How many bottl

Natasha_Volkova [10]

Divide total cups he drank by the # of cups in each bottle.

7 ÷ 3= 2.3333

Since each bottle only holds 3 cups, he drank 3 bottles of water. He didn't drink all the water in the third bottle, but he started drinking the third bottle.

ANSWER: 3 bottles

Hope this helps! :)

4 0

3 years ago

How do u subtract fractions

Gnoma [55]

Like fractions are fractions with the same denominator. You can add and subtract like fractions easily - simply add or subtract the numerators and write the sum over the common denominator.

Before you can add or subtract fractions with different denominators, you must first find equivalent fractions with the same denominator, like this:

1.Find the smallest multiple (LCM) of both numbers.

2.Rewrite the fractions as equivalent fractions with the LCM as the denominator.

When working with fractions, the LCM is called the least common denominator (LCD)

7 0

4 years ago

Read 2 more answers

CAN YOU GUYS PLEASE HELP ME WITH THESE QUESTIONS...ITS WORTH 50 POINTS..AND I WILL MARK BRAINLY pt2.

Pavel [41]

Answer: what i would do is add a zero

Step-by-step explanation:

hope that help u have a wonderful day

7 0

3 years ago

NEED HELP FOR EXAMS TOMORROW

alexandr1967 [171]

Answer:

also got exams

Step-by-step explanation:

good luck bro

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

6 0

3 years ago