2(b + 3c) → We first need to simplify this.
Simplify.
2b + 6c
1st Option :
3(b + 2c)
Simplify.
3b + 6c
This is INCORRECT, as it is not equal to 2b + 6c.
2nd Option :
(b + 3c) + (b + 3c)
Simplify.
2b + 6c
This is CORRECT because 2b+6c = 2b+6c
(b + 3c) + (b + 3c) → Answer
~Hope I helped!~
Answer:
C
Step-by-step explanation:
If you look closely.. You can see that one is longer than the other
Answer:
Step-by-step explanation:
The wording on this is not the best. It sounds like the 1 zero has even multiplicity (that's because of where the modifier is). On top of that it has an odd power. You could try this. y =x*(x^2+1)^2
The problem is not with the power. It gives x^5. The problem is with the multiplicity of the one place where it crosses. (X^2 + 1) does factor, but it gives a complex root. I'm not sure that's allowed. However, it is the best I can do.
Answer:
2.17609
Step-by-step explanation:
Easiest and fastest way is to just directly plug log base 10 of 150 into the calc, as it is a nasty decimal.
