the question in English is
<span>The difference between 3/2 of Adriana's age and her age decreased by 6 is less than her age. In addition, the difference between three times her age and her age increased by 14 is less than her age. At what stage of her development is Adriana?
Let
x---------> Adriana s age
we know that
(3/2)x-(x-6) < x------> (3/2)x-x+6 < x----->(1/2)x-x < -6----> (1/2)x > 6
x> 12
and
3x-(x+14) < x-----> 3x-x-14 < x------> 2x-x < 14----> x < 14
the solution for the age of Adriana is the interval (12,14)
the answer is
</span>Adriana is in the adolescence stage
the answer in Spanish
Hagamos
x---------> La edad de Adriana
Sabemos que
(3/2)x-(x-6) < x------> (3/2)x-x+6 < x----->(1/2)x-x < -6----> (1/2)x > 6
x> 12
y tambien que
3x-(x+14) < x-----> 3x-x-14 < x------> 2x-x < 14----> x < 14
La solucion para la edad de Adriana es el intervalo (12,14)
La respuesta es
Adriana se encuentra en la etapa de adolescencia
Answer:
d=4
Step-by-step explanation:
(12d - 24) - (2 • (d - 3) + 22) = 0
10d - 40 = 10 • (d - 4)
10 • (d - 4) = 0
Solve : 10 = 0
Solve : d-4 = 0
Add 4 to both sides of the equation :d = 4
Answer: close to 400 times but probably not exactly 400 times
Step-by-step explanation:
2400÷6= 400
