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3 years ago

Can somebody help me???!!!!:/

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

3 0

$26,000,000,000=2.6\cdot10^{10}\\\\
\dfrac{4.94\cdot10^{13}}{2.6\cdot10^{10}}=\boxed{1.9\cdot10^3}$

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The random variable X~(30,2^2) Find p(X<33) Find p(X>26)

Ostrovityanka [42]

Answer:

i) P(X<33) = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

Step(ii):-

Given that the random variable X = 33

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-30}{2} = 1.5$ >0

P(X<33) = P( Z<1.5)

= 1- P(Z>1.5)

= 1 - ( 0.5 - A(1.5))

= 0.5 + 0.4232

P(X<33) = 0.9232

Step(iii) :-

Given that the random variable X = 26

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-26}{2} = 3.5$ >0

P(X>26) = P( Z>3.5)

= 0.5 - A(3.5)

= 0.5 - 0.4990

= 0.001

P(X>26) = 0.001

5 0

3 years ago

Please answer question 4

olasank [31]

#4)
cross multiply
2(8x+10) = 4 * 5x
16x + 20 = 20x
4x = 20
x = 5

3 0

3 years ago

What is the HCF of 96 and 108

mash [69]

The answer is 12 good luck;)

4 0

3 years ago

2/3 is what percent of 1/4?

saveliy_v [14]

So if we take 1/4 to be the 100%, what is 2/3 in percentage off of it then?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{4}&100\\\\
\frac{2}{3}&p
\end{array}\implies \cfrac{\frac{1}{4}}{\frac{2}{3}}=\cfrac{100}{p}\implies \cfrac{1}{4}\cdot \cfrac{3}{2}=\cfrac{100}{p}\implies \cfrac{3}{8}=\cfrac{100}{p}
\\\\\\
p=\cfrac{8\cdot 100}{3}\implies p=\cfrac{800}{3}\implies p=266\frac{2}{3}\implies p\approx 266.\overline{66}$

yes, is a large value, because 2/3 is indeed larger than 1/4, more than twice as large.

8 0

3 years ago

To find g(x + 7), what do you substitute for x in the function g(x) = 4x - 2?

AlexFokin [52]

Answer: x+7

Step-by-step explanation:

g(x) = 4x - 2

g(x+7)=4(x+7)-2

Substitute (x+7)

8 0

2 years ago