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3 years ago

Can somebody help me???!!!!:/

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

3 0

$26,000,000,000=2.6\cdot10^{10}\\\\
\dfrac{4.94\cdot10^{13}}{2.6\cdot10^{10}}=\boxed{1.9\cdot10^3}$

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Determine the area of the parallelogram below

spayn [35]

Answer:

A= BH

A=8cm ×2.2 cm

A= 17.6cm²

8 0

3 years ago

I need help with this question and no link or I’ll report u

Ugo [173]

It would be 35 because we can assume that both y’s on the left side are parallel to the right side, and so they would have to be a 35 on each side

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3 years ago

Simplify the expression if possible 4^3 × 4^5 and write you answer as a power ( using exponents )

alexgriva [62]

Answer:

4^8

Step-by-step explanation:

If you are multiplying two bases that are the same with different exponents, the exponents get added and the base stays the same:

$x^a*x^b=x^{a+b}\\\\4^3*4^5=4^{3+5}\\\\4^3*4^5=4^8$

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2 years ago

What are the values of u and v

lubasha [3.4K]

Answer:

u=72

v=61

Step-by-step explanation:

for U:

54+54=108

180-108=72

For V:

180-58=122

122/2=61

5 0

3 years ago

Gekata [30.6K]

Answer: the system has no solution.

Step-by-step explanation:

\displaystyle\\

\left \{ {{x^2y=16\ \ \ \ \ (1)} \atop {x^2+4y+16=0\ \ \ \ \ (2)}} \right. .\\

Multiply\ both\ sides\ of\ the\ equation\ (2)\ by\ y\ (y\neq 0):\\

x^2y+4y^2+16y=0\\

We\ substitute\ equation\ (1)\ into\ equation\ (2):\\

16+4y^2+16y=0\\

4y^2+16y+16=0\\

4*(y^2+4y+4)=0\\

4*(y^2+2*y*2+2^2)=0\\

4*(y+2)^2=0\\

Divide\ both\ sides\ of\ the \ equation\ by\ 4:\\

(y+2)^2=0\\

(y+2)*(y+2)=0\\

So,\ y+2=0\\

y=-2.\\

$\displaystyle\\We\ substitute\ the\ value\ of\ y\ into\ equation\ (1):\\x^2*(-2)=16\\Divide\ both\ sides\ of\ the \ equation\ by\ -2:\\x^2=-8\\x^2\geq 0\\ Hence,\ the\ system\ has\ no\ solution.$

7 0

2 years ago