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aleksandrvk [35]
3 years ago
12

An encryption system works by shifting the binary value for a letter one place to the left. "A" then becomes: 1 1 0 0 0 0 1 0 Th

is binary value is then converted to hexadecimal; the hexadecimal value for "A" will be:
Computers and Technology
1 answer:
Vika [28.1K]3 years ago
8 0

Answer:

The hexadecimal equivalent of the encrypted A is C2

Explanation:

Given

Encrypted binary digit of A = 11000010

Required

Hexadecimal equivalent of the encrypted binary digit.

We start by grouping 11000010 in 4 bits

This is as follows;

1100 0010

The we write down the hexadecimal equivalent of each groupings

1100 is equivalent to 12 in hexadecimal

So, 1100 = 12 = C

0010 is represented by 2 in hexadecimal

So, 0010 = 2

Writing this result together; this gives

1100 0010 = C2

Going through the conversion process;

A is first converted to binary digits by shifting a point to the left

A => 11000010

11000010 is then converted to hexadecimal

11000010 = C2

Conclusively, the hexadecimal equivalent of the encrypted A is C2

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Try to crack the code:
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3 0
2 years ago
A. Calculate the diffusion coefficient for magnesium in aluminum at 450°C.
SIZIF [17.4K]

Answer:

a) D = 4.88 * 10^(-14) m^2 / s

b)   <em>t </em>= 1.1 hr

Solution:

a) Magnesium in Aluminum diffusion:

D = Do * exp(-Qd / RT)

  =  (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)

  = 4.88 * 10^(-14) m^2 / s

D = 4.88 * 10^(-14) m^2 / s

b) The composition remains same at say the distance Xo:

(Cx - Co) / (Cs - Co) = Constant

Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15

D_{550} * <em>t </em>= D_{450} * 15

(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>

(4.88 * 10^(-14) m^2 / s) * 15

by, solving for <em>t </em>we get:

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5 0
3 years ago
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Marina CMI [18]

Answer:

i. This value was not accepted because we have 12 months and not 13.

ii. This is because the user entered the value for the day as value for the month.

Explanation:

i. Why was this not accepted?

This value was not accepted because we have 12 months and not 13. The user entered a value that was above the maximum value registered for the number of months in a year- which is 12.

ii. Why do you think this error occurred

This is because the user entered the value for the day as value for the month.

This could be because the user uses a date system different from that of the program.

3 0
2 years ago
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