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2 years ago

Calcium carbonate decomposes at high temperatures to give calcium oxide and carbon

Chemistry

1 answer:

Dafna1 [17]2 years ago

4 0

Answer:

Explanation:

Calcium carbonate decomposes at high temperatures to give calcium oxide and carbon

dioxide as shown below.

CaCO3(s) = CaO(s) + CO2(g)

The Kp for this reaction is 1.16 at 800°C. A 5.00 L vessel containing 10.0 g of CaCO3(s)

was evacuated to remove the air, sealed, and then heated to 800°C. Ignoring the volume

occupied by the solid, what will overall mass percent of carbon in the solid once equilibrium is reached?

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Determine the molality of a solution of methanol dissolved in ethanol for which the mole fraction of methanol is 0.135. Give you

Alja [10]

Answer: The molality of the solution is 0.11 m

Explanation:

We are given:

Mole fraction of methanol = 0.135

This means that 0.135 moles of methanol is present in 1 mole of a solution

Moles of ethanol = 1 - 0.135 = 0.865 moles

To calculate the mass for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of ethanol = 0.865 moles

Molar mass of ethanol = 46 g/mol

$0.865mol=\frac{\text{Mass of ethanol}}{46g/mol}\\\\\text{Mass of ethanol}=(0.865mol\times 46g/mol}=39.79g$

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

Where,

$m_{solute}$ = Given mass of solute (methanol) = 0.135 g

$M_{solute}$ = Molar mass of solute (methanol) = 32 g/mol

$W_{solvent}$ = Mass of solvent (ethanol) = 39.79 g

Putting values in above equation, we get:

$\text{Molality of methanol}=\frac{0.135\times 1000}{32\times 39.79}\\\\\text{Molality of methanol}=0.106m\approx 0.11m$

Hence, the molality of the solution is 0.11 m

6 0

3 years ago

Tellurium is a period 5 chalcogen. Selenium is a period 4 chalcogen. If the only factor affecting ionization energies was the nu

notsponge [240]

Answer:

yes

Explanation: took quiz

4 0

2 years ago

g If you have three identical containers (same volume) at the same temperature and pressure, each with a different gas. Containe

vekshin1

Answer:

The three gases, in the three identical containers, will all have the same number of molecules

Explanation:

If these three gases (Helium He, Neon Ne, and Oxygen $O_{2}$ ) are all contained in separate identical containers with the same volume. And they are all stored at the same temperature, and pressure. Then, they'll all contain the same number of molecules. This is in line with Avogadro's law which states that "Equal volume of all gases, at the same temperature and pressure, have the same number of molecules."