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Ket [755]
2 years ago
14

Calcium carbonate decomposes at high temperatures to give calcium oxide and carbon

Chemistry
1 answer:
Dafna1 [17]2 years ago
4 0

Answer:

Explanation:

Calcium carbonate decomposes at high temperatures to give calcium oxide and carbon

dioxide as shown below.

CaCO3(s) = CaO(s) + CO2(g)

The Kp for this reaction is 1.16 at 800°C. A 5.00 L vessel containing 10.0 g of CaCO3(s)

was evacuated to remove the air, sealed, and then heated to 800°C. Ignoring the volume

occupied by the solid, what will overall mass percent of carbon in the solid once equilibrium is reached?

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How many moles of aluminum oxide al2o3 are in a sample with a mass of 204.0
erik [133]

Answer:

2 moles

Explanation:

Let us first start by calculating the molecular mass of Al₂O₃.

The mass of a mole of any compound is called it's molar mass. 1 molar mass 6.02 X 10²³, or Avogadro's number, of compound entities.

Say, 1 mole of Al₂O₃ has 6.02 X 10²³ of Al₂O₃ molecules/atoms. It also has 2*6.02 X 10²³ number of Al atoms and 3*6.02 X 10²³ number of O atoms.

Molecular mass of Al : 26.981539 u

Molecular mass of O: 15.999 u

Therefore, molecular mass of Al₂O₃ is:

= (2*26.981539) + (3*15.999) u

= 101.960078 u

This can be approximated to 102 u.

1mole weighs 102 u

So, 2moles will weigh 2*102 = 204 u

3 0
3 years ago
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Llana [10]

Answer:

B. Is the correct answer :) i hope this helps!!

Explanation:

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8 0
3 years ago
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lana [24]

Answer:

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Explanation:

8 0
2 years ago
HELP!!!!!What is the molar mass of a gas which has a density of .249 g/L at 20.0 degrees Celsius and a pressure of .95 atm?
fgiga [73]

Answer:

6.31g/mol

Explanation:

Using the ideal gas equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

Mole (n) = mass (m)/molar mass (Mm)

* Mm = m/n

Also, density (p) = mass (m) ÷ volume (V)

PV = nRT

Since n = M/Mm

PV = M/Mm. RT

PV × Mm = m × RT

Divide both sides by V

P × Mm = m/V × RT

Since p = m/V

P × Mm = p × RT

Mm = p × RT/P

Mm = 0.249 × 0.0821 × 293/0.95

Mm = 5.989 ÷ 0.95

Mm = 6.31g/mol

7 0
3 years ago
What design element of an astronaut's spacesuits protects him or her from micrometeoroids, which are tiny bits of space debris t
leonid [27]

Answer:

Tough outer shell

Explanation:

Three types of space suits based on their purpose are IVA (Intravehicular activity), EVA (extravehicular activity), and IEVA (intra/extravehicular activity)

Space suits have an outer layer known as the Integrated Thermal Micrometeoroid Garment also known as the TMG or ITMG

The functions of the TMG includes the provision of an insulation medium to the wearer of the suit thereby preventing loss of heat and keeping the wearer warm, protect the wearer from solar radiation which are harmful as well as from Micrometeoroid and debris orbiting in space known as MMOD

The outermost layer of the EMU TMG suits is white Ortho-Fabric that consists of Nomex, Kevlar and Gore-Tex, making it fire resistant, very strong and very tough, and water proof as well as breathable.

3 0
3 years ago
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