<h2>Answer:</h2>
Moles of a gas = 0.500
Volume = 2.50 L
Pressure = 13. atm
Temperature = ?
Solution:
Formula:
PV = n RT
Putting the values in formula:
T = PV/nR = 13 * 2.5 / 0.5 * 0.082057
= 32.5/0.041 = 792.68 K
T = 792.68 K
<span>(a) what is the average volume (in cubic meters) required for each iron atom
For this case, the density of Iron would be </span>7.87g/cm³
<span>
V = 9.27 x 10^-26 kg / </span>7.87g/cm<span>³ ( 1 kg / 1000 g)
</span>V = 1.18 x 10-23 cm³<span>
(b) what is the distance (in meters) between the centers of adjacent atoms?
We assume the atoms as cube, so we use the volume of the cube to calculate the distance of the atoms.
V = </span>1.18 x 10-23 cm<span>³ = s</span>³
s = 2.28 x 10^-8 cm
You have to do it to see the results