All categories

2 years ago

Convert the following into correct scientific notation:

Chemistry

1 answer:

s2008m [1.1K]2 years ago

8 0

Answer:

4.963x 10²

7.8761x 10³

8.9 x 10⁻²

Explanation:

Scientific notation is the way to express the large value in short form.

The number in scientific notation have two parts.

. The digits (decimal point will place after first digit)

× 10 ( the power which put the decimal point where it should be)

for example the number 6324.4 in scientific notation will be written as = 6.3244 × 10³

a) 496.3 x 10²

4.963x 10²

b) 7876.1 x 10⁻⁷

7.8761x 10³

c) 0.089 x 10⁻⁹

8.9 x 10⁻²

You might be interested in

Which type of fertilization is common with animals that live in the water?

Makovka662 [10]

External fertilization in animals usually occurs in water or in damp areas in a process called spawning.

5 0

2 years ago

Read 2 more answers

Geologists may choose to lick a mineral to identify it. What mineral is the geologist expecting with this test?

Archy [21]

NaCl (halite) or KCl (sylvite)

8 0

3 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 Pb(ClO3)2 with aqueous NaI . NaI. Include phases. chemica

FinnZ [79.3K]

Answer: The mass of precipitate (lead (II) iodide) that will form is 119.89 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI solution = 0.130 M

Volume of solution = 0.400 L

Putting values in above equation, we get:

$0.130M=\frac{\text{Moles of NaI}}{0.400L}\\\\\text{Moles of NaI}=(0.130mol/L\times 0.400L)=0.52mol$

The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

The precipitate (insoluble salt) formed is lead (II) iodide

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.52 moles of NaI will produce = $\frac{1}{2}\times 0.52=0.26mol$ of lead (II) iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of lead (II) iodide = 0.26 moles

Molar mass of lead (II) iodide = 461.1 g/mol

Putting values in above equation, we get:

$0.26mol=\frac{\text{Mass of lead (II) iodide}}{461.1g/mol}\\\\\text{Mass of lead (II) iodide}=(0.26mol\times 461.1g/mol)=119.89g$

Hence, the mass of precipitate (lead (II) iodide) that will form is 119.89 grams

4 0

3 years ago

compared to maximum number of electrons that can occupy the d sublevel the max number of electrons that can occupy s sublevel

morpeh [17]

D-sublevel can occupy 10 electrons whereas s-sublevel can occupy 2 electrons...

5 0

3 years ago

What is the general structure for a chemical equation?

kramer

A chemical formula is a way of expressing information about the proportions of atoms that constitute a particularchemical compound, using a single line of chemical element symbols, numbers, and sometimes also other symbols, such as parentheses, dashes, brackets, commas and plus (+) and minus (−) signs. A chemical formula is not a chemical name showing how the atoms are arranged.

6 0

3 years ago