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Jet001 [13]
3 years ago
11

A bus and a car leave the same place and traveled in opposite directions. If the bus is traveling at 50 mph and the car is trave

ling at 55 mph, in how many hours will they be 210 miles apart?
Mathematics
1 answer:
harina [27]3 years ago
6 0

Answer:

After Two Hours.

Step-by-step explanation:

A simple way to do it is to:

1. Add 50+55, it is equal to 105. This is after one hour, so we know that it's more than this.

2. Add 50+55 to 105, This is after two hours, and we get 210, so we know that it has to be equal to 2 hours.

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lbvjy [14]
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7 0
4 years ago
Read 2 more answers
g European roulette. The game of European roulette involves spinning a wheel with 37 slots: 18 red, 18 black, and 1 green. A bal
butalik [34]

Answer:

The expected value and standard deviation of your total winnings are -$0.081 and $3 respectively.

Step-by-step explanation:

We are given that the game of European roulette involves spinning a wheel with 37 slots: 18 red, 18 black, and 1 green.

Gamblers can place bets on red or black. If the ball lands on their color, they double their money. If it lands on another color, they lose their money.

Let the probability of the ball landing on red slot = \frac{18}{37}

The probability of the ball landing on black slot = \frac{18}{37}

The probability of the ball landing on green slot = \frac{1}{37}

Now, it is stated that Gambler can place bets only on the red or black slot, so;

The probability of winning the bet will be = \frac{18}{37}

and the probability of losing the bet will be = \frac{18}{37}+\frac{1}{37}

                                                                        = \frac{19}{37}

If the gambler wins he gets $3 and if he loses he will get -$3.

So, the expected value of gambler's total winnings is given by;

E(X) = \sum X \times P(X)

        = \$3 \times \frac{18}{37} + (-\$3 \times \frac{19}{37})

        = \$3 \times (-\frac{1}{37})  = -$0.081

Now, the standard deviation of gambler's total winnings is given by;

S.D.(X) = \sqrt{(\sum X^{2}  \times P(X))-(\sum X \times P(X))^{2} }

So, E(X^{2})=\sum X^{2}  \times P(X)

                 = \$3^{2}  \times \frac{18}{37} + (-\$3^{2}  \times \frac{19}{37})

                 = \$9 \times (\frac{18}{37}+\frac{19}{37})  = $9

Now, S.D.(X) = \sqrt{\$9-(-\$0.081)^{2} }

                     = \sqrt{8.993}  = $2.99 ≈ $3

Hence, the expected value and standard deviation of your total winnings are -$0.081 and $3 respectively.

6 0
3 years ago
(9/15)=(15C9)(.75)^9(.15)^(15-7)<br><br> math 120 prob and stats<br><br> pls help asap
Lynna [10]
<h3>Answer:  9</h3>

======================================================

Explanation:

You're on the right track. The 15 C 9 refers to the nCr combination formula which is built into the binomial probability.

The 0.75^9 is also correct

The 0.15^(15-7) portion is not correct. That 0.15 should be 0.25 so it adds to 0.75 to get 1.00 or just 1

Also, the (15-7) portion should be (15-9)

-----------------------------------

So here's how the steps should look

B(x) = probability of getting a certain x value in a binomial distribution

B(x) = (nCx)*(p)^(x)*(1-p)^(n-x)

B(9) = (15C9)*(0.75)^(9)*(1-0.75)^(15-9)

B(9) = 5005*(0.75)^(9)*(0.25)^(6)

B(9) = 0.09174776729197

B(9) = 0.0917

The probability of getting exactly 9 flights on time is roughly 0.0917

This applies to one trial.

In 100 trials, we expect about 100*0.0917 = 9.17 = 9 flights to be on time.

It's a coincidence that we get a final answer of 9 which matches with the other 9 mentioned in the instructions. This won't always be the case.

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The principal Po is invested in an account that pays an annual interest rate r (written as a decimal), compounded n times per ye
AVprozaik [17]
At the end of the first year, the correct formula is this one:
P=P_0(1+r)
The second year, we add r times the above amount, we get:
P_0(1+r)+r(P_0(1+r))=P_0(1+2r+r^2)\\=P_0(1+r)^2
Iterating the process, we get the general formula of any number of years:
P=P_0(1+r)^n
6 0
3 years ago
Given the equation 28m4 + 40m3 + 8m, find<br> the greatest common factor (GCF).
svet-max [94.6K]
4m is the greatest common factor
8 0
3 years ago
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