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2 years ago

A = (-123) + 77 + (-257) + 23 – 43

Mathematics

1 answer:

irga5000 [103]2 years ago

7 0

Answer:

$A=-323$

Step-by-step explanation:

A = (-123)+77+(-257)+23-43

A = -46+(-257)+23-43

A = -303+23-43

A = -280-43

A = -323

Hope this helps

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Holly wants to save money for an emergency. Holly invests 1,500 in an account that pays an interest rate of 6.75%. How many year

lina2011 [118]

The formula is
A=p (1+r)^t
A future value 7300
P present value 1500
R interest rate 0.0675
T time?
7300=1500 (1+0.0675)^t
Solve for t
Divide both sides by 1500
7300/1500=1.0675^t
Take the log for both sides
Log (7300/1500)=t×log (1.0675)
Divide both sides by log (1.0675)
T=log(7,300÷1,500)÷log(1.0675)
T=24.2 years round your answer to get 24 years

Hope it helps!

4 0

3 years ago

Read 2 more answers

According to the graph, what is the value of the constant in the equation

wolverine [178]

The question is missing the graph. So, it is attached below.

Answer:

(D) 3.2

Step-by-step explanation:

Given:

A graph of height versus width.

The equation given is:

Height = constant × Width

Rewriting in terms of 'constant'. This gives,

$\textrm{Constant}=\frac{Height}{Width}$ ------------- (1)

The width is plotted on the X-axis and the corresponding height is plotted on the Y-axis.

The four points plotted on the line are:

$(x, y) = (0.5, 1.6), (1, 3.2), (2, 6.4)\ and\ (3, 9.6)$ .

Now, any point will satisfy equation (1).

Consider the point (0.5, 1.6). So, height = 1.6 and width = 0.5. Therefore,

$\textrm{Constant}=\frac{Height}{Width}\\\\\textrm{Constant}=\frac{1.6}{0.5}=3.2$

Also, we observe that for all the remaining points,

$\dfrac{3.2}{1}=\dfrac{6.4}{2}=\dfrac{9.6}{3}=3.2$ .

Hence, the value of the constant is 3.2.

Option (D) is correct.

4 0

2 years ago

A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground. which equation can be used to determine the

3241004551 [841]

Answer:

$h(t)=-16t^2+85t+28$ is equation of height of rocket.

Option D is correct.

Step-by-step explanation:

Given: A rocket is launched with speed 85 ft/s from a height 28 feet.

Launching a rocket follows the path of parabola. The equation of rocket should be parabolic.

Parabolic equation of rocket is

Formula: $h(t)=\dfrac{1}2gt^2+v_0t+h_0$

g ⇒ acceleration due to gravity (-32 ft/s)

v ⇒ Initial velocity ( $v_0=85\ ft/s$ )

h ⇒ Initial height ( $h_0=28\ feet$ )

h(t) ⇒ function of height at any time t

Substitute the given values into formula

$h(t)=\frac{1}{2}(-32)t^2+(85)t+28$

$h(t)=-16t^2+85t+28$

D is correct.

6 0

3 years ago

Read 2 more answers

18. On Monday, Mr Tan earned a total of $1260 from the sale of some toys. On the next day, he earned a total of $1736 from the s

GalinKa [24]

Answer:

Monday 45

Tuesday 62

Step-by-step explanation:

It's asking you to find the common factor. 28 goes into both of these numbers. So do 1260÷28 and 1736÷28

6 0

2 years ago

If $5200 is invested at a rate of 8.6% compounded quarterly, how long will it take, to the nearest hundredth of a year, until th

dexar [7]

Answer:

$t= 9.43\ years$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=?\ years\\ P=\$5,200\\ r=8.6\%=8.6\100=0.086\\n=4\\A=\$11,600$

substitute in the formula above

$11,600=5,200(1+\frac{0.086}{4})^{4t}$

$11,600=5,200(1.0215)^{4t}$

$(11,600/5,200)=(1.0215)^{4t}$

Applying log both sides

$log(11,600/5,200)=log(1.0215)^{4t}$

applying property of logarithms

$log(11,600/5,200)=(4t)log(1.0215)$

$t=log(11,600/5,200)/[(4)log(1.0215)]$

$t= 9.43\ years$

5 0

3 years ago