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BabaBlast [244]
4 years ago
7

For a given input value q, the function f outputs a value r to satisfy the following equation. 11q-4=3r-6, Write a formula for f

(q) in terms of q
Mathematics
2 answers:
Jlenok [28]4 years ago
7 0
Q=2, r=8
11(2)= 3(8)-2
22=24-2
22
ohaa [14]4 years ago
7 0

Answer with Step-by-step explanation:

For a given input value q, the function f outputs a value r

⇒ f(q)=r

11q-4=3r-6

⇒ 3r=11q-4+6

⇒ 3r=11q+2

⇒ r=(11q+2)/3

⇒ f(q)=(11q+2)/3

Hence, formula for f(q) in terms of q is:

\dfrac{11q+2}{3}

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Step-by-step explanation:

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Hope it helps you in your learning process

6 0
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b is the midpoint of AC and E is the midpoint of BD if A(-9,-4) C(-1,6) and E(-4,-3) find the coirdinates of D
natima [27]

To find the coordinate of the point D, we can use the Midpoint point of a line Segment formula. Calculation of the formula are as follows,

Given two points A(x1,y1) and C(x2,y2), we need to locate the midpoint coordinate of this line denoted as B(x,y).

To solve for the value of x and y, we get,

x=(x1+x2)/2 and y=(y1+y2)/2

For the given problem, we need to solve first the midpoint coordinate of AC which is B.

So, A(-9,-4)=A(x1,y1) and C(-1,6)=C(x2,y2)

Hence,

B(x,y)=B((-9+(-1))/2, (-4+6)/2)=B(-10/2,2/2)=B(-5,1)

Now, since the midpoint is given but one point in the line is missing. To solve for the missing point D(x2,y2), we need to use the Midpoint Segment Formula.

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So,

x=(x1+x2)/2 and y=(y1+y2)/2

-5=(-4+x2)/2 and 1=(-3+y2)/2

By Cross Multiplication and Transposing method,

-5(2)=-4+x2 and 1(2)=-3+y2

x2=-10+4=-6 and y2=3+2=5

Thus, the coordinate of D is D(-6,5).

5 0
4 years ago
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ICE Princess25 [194]
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3 0
3 years ago
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Crank

Answer:

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Step-by-step explanation:

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5 0
3 years ago
4x + 3x - 4 ..................................................
Lapatulllka [165]

Answer:

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is the answer for that question

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