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3 years ago

Write this number in expanded form. 354,782

Mathematics

2 answers:

LuckyWell [14K]3 years ago

5 0

Three hundred fifty four thousand seven hundred eighty two

Or

300,000+50+4+700+80+2

Luda [366]3 years ago

3 0

300,000 + 50,000 + 4,000 + 700 + 80 + 2
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Determine the number of crawlers and rovers to make,that will maximize the company profit in a given week

Dmitriy789 [7]

Answer:

jjjijijijiiijijijijijijij no pliss inglés. ;D.

8 0

2 years ago

Factor 81z^4 - 16<br> Please answer asap

Oksanka [162]

81x%5E4-16 Start with the given expression.

%289x%5E2%29%5E2-16 Rewrite 81x%5E4 as %289x%5E2%29%5E2.

%289x%5E2%29%5E2-%284%29%5E2 Rewrite 16 as %284%29%5E2.

Notice how we have a difference of squares A%5E2-B%5E2 where in this case A=9x%5E2 and B=4.

So let's use the difference of squares formula A%5E2-B%5E2=%28A%2BB%29%28A-B%29 to factor the expression:

A%5E2-B%5E2=%28A%2BB%29%28A-B%29 Start with the difference of squares formula.

%289x%5E2%29%5E2-%284%29%5E2=%289x%5E2%2B4%29%289x%5E2-4%29 Plug in A=9x%5E2 and B=4.

So this shows us that 81x%5E4-16 factors to %289x%5E2%2B4%29%289x%5E2-4%29.

In other words 81x%5E4-16=%289x%5E2%2B4%29%289x%5E2-4%29.

Now let's factor 9x%5E2-4 further

-------------------------------------

9x%5E2-4 Start with the given expression.

%283x%29%5E2-4 Rewrite 9x%5E2 as %283x%29%5E2.

%283x%29%5E2-%282%29%5E2 Rewrite 4 as %282%29%5E2.

Notice how we have a difference of squares A%5E2-B%5E2 where in this case A=3x and B=2.

So let's use the difference of squares formula A%5E2-B%5E2=%28A%2BB%29%28A-B%29 to factor the expression:

A%5E2-B%5E2=%28A%2BB%29%28A-B%29 Start with the difference of squares formula.

%283x%29%5E2-%282%29%5E2=%283x%2B2%29%283x-2%29 Plug in A=3x and B=2.

So this shows us that 9x%5E2-4 factors to %283x%2B2%29%283x-2%29.

In other words 9x%5E2-4=%283x%2B2%29%283x-2%29.

----------------------------------------------------------------

Answer:

So 81x%5E4-16 completely factors to %289x%5E2%2B4%29%283x%2B2%29%283x-2%29

3 0

2 years ago

Ardem collected data from a class survey. He then randomly selected samples of five responses to generate four samples.

scoundrel [369]

Solution: The sample mean of sample 1 is:

$\bar{x}=\frac{4+5+2+4+3}{5}= \frac{18}{5}=3.6$

The sample mean of sample 2 is:

$\bar{x}=\frac{2+2+6+5+7}{5}= \frac{22}{5}=4.4$

The sample mean of sample 3 is:

$\bar{x}=\frac{4+6+3+4+1}{5}= \frac{18}{5}=3.6$

The sample mean of sample 4 is:

$\bar{x}=\frac{5+2+4+3+6}{5}= \frac{20}{5}=4$

The minimum sample mean of the four sample means is 3.6 and maximum sample mean of the four sample means is 4.4.

Therefore, using his four samples, between 3.6 and 4.4 will Ardem's actual population mean lie.

Hence the option 3.6 and 4.4 is correct

6 0

3 years ago

Read 2 more answers

Write 18 1/4 as a decimal

nevsk [136]

Answer:

18.25

Step-by-step explanation:

1/4 = 0.25

7 0

2 years ago

Read 2 more answers

The following table gives results from two groups of students who took a nonproctored test. Use a 0.01 significance level to tes

Nana76 [90]

Answer:

Original claim is $\mu_{1} =\mu_{2}$

Opposite claim is $\mu_{1} \neq \mu_{2}$

Null and alternative hypotheses:

$H_{0}:\mu_{1} = \mu_{2}$

$H_{1} : \mu_{1} \neq \mu_{2}$

Significance level: 0.01

Test statistic:

We can use TI-84 calculator to find the test statistic and P-value. The steps are as follows:

Press STAT and the scroll right to TESTS

Scroll down to 2-SampTTest... and scroll to stats.

Enter below information.

$\bar{x_{1}}=70.29$

$Sx1=22.09$

$n_{1} = 30$

$\bar{x_{2}}=74.26$

$Sx2=18.15$

$n_{2} = 32$

$\mu_{1} \neq \mu_{2}$

Pooled: Yes

Calculate.

The output is in the attachment.

Therefore, the test statistic is:

$t=-0.78$

P-value: 0.4412

Reject or fail to reject: Fail to reject

Final Conclusion: Since the p-value is greater than the significance level, we, therefore, fail to reject the null hypothesis and conclude that the there is sufficient evidence to support the claim that the samples are from populations with the same mean.

6 0

2 years ago