If you would like to know what is the sum of 667 and 23, you can calculate this using the following steps:
the sum of 667 and 23:
667 + 23 = 690
The correct result would be B. 690.
Answer with Step-by-step explanation:
We are given that A, B and C are subsets of universal set U.
We have to prove that

Proof:
Let x
Then
and 
When
then
but 
Therefore,
but 
Hence, it is true.
Conversely , Let
but 
Then
and
When
then 
Therefor,
Hence, the statement is true.
Answer:
The first one
Step-by-step explanation:
Since only the first session is $10, it wouldn't be 10x.
The second session is $5, and it will never be $10 again, so $5 sessions are unlimited which would be 5x.
So the answer is y = 10 + 5x
(sorry if i didnt explain well)
Answer:120 units
Step-by-step explanation:
Evaluate the given function in x=-4.
This is, replace the x in the function for -4 and find the value of g(-4).

The value of g(-4) is 32.