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Airida [17]
3 years ago
8

3x+4y=5

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0
3x + 4y = 5
2x - 5y = 8
 
To answer this question, we need to put both of these equations into Slope-Intercept form, or in other words, solve for y.

3x + 4y = 5            Subtract 3x from both sides
        4y = -3x + 5   Divide both sides by 4
          y = -\frac{3}{4} + \frac{5}{4}

2x - 5y = 8   Subtract 2x from both sides
      -5y = -2x + 8   Divide both sides by -5
         y = \frac{2}{5} - \frac{8}{5}

When you look at the two equations, you can see that their slopes are completely different, so they aren't parallel, or inconsistent. Since  \frac{2}{5} is not the same as<span> -\frac{3}{4}, they aren't the same line, or dependent. So, the only option left is that they are consistent and independent.</span>
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Equation fo a circle:
Data:
Center: C(x₀,y₀).
radius: r

(x-x₀)²+(y-y₀)²=r²

In this equation:
(x+4)²+(y-6)²=25
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r²=25  ⇒r=√25=5

Then, it´s radius is 5.

If, we have got two points:
A(x₁,y₁)
B(x₂,y₂)
The distance beetween the points is:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²]

Then:
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B(-1,-5)

dist(A,B)=√[(-1+6)²+(-5-7)²]
dist (A,B)=√(5²+12²)
dist (A,B)=√(25+144)
dist (A,B)=√169
dist (A,B)=13

the distance between the points (-6,7) and (-1,-5) is 13.


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