The first one would be x^12
The equation of a circle is written as ( x-h)^2 + (y-k)^2 = r^2
h and k is the center point of the circle and r is the radius.
In the given equation (x+3)^2 + (y-1)^2 = 81
h = -3
k = 1
r^2 = 81
Take the square root of both sides:
r = 9
The center is (-3,1) and the radius is 9
I can't think of what the form is called, but the slope is in that equation.
y=mx+b
m is the slope and in that equation, m=-4/3
Step-by-step explanation:
4x > 36-4
4x > 32 (divide both sides of the inequality by 4 )
4x ÷ 4 > 32 ÷ 4
x > 8
