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Brums [2.3K]
4 years ago
13

Given that loga11 = 2.398, and loga5 = 1.609, find loga. 11/5

Mathematics
1 answer:
Ilya [14]4 years ago
8 0
\bf \textit{Logarithm of rationals}\\\\
log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)\\\\
-------------------------------\\\\
log_a\left( \frac{11}{5} \right)\implies log_a(11)-log_a(5)\implies 2.398~-~1.609\implies 0.789
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