Answer:
(-5,1) would be the coordinates of its image
Answer:
( 0.6 t^2 + 3t + 11 ) cm
Step-by-step explanation:
dh/dt = 1.2t + 3
at t = 0, h = 11 cm
(a)
dh / dt = 1.2 t + 3
dh = (1.2 t + 3) dt
integrate on both sides
h = 0.6 t^2 + 3t + c .... (1)
where c is the integrating constant
put t = 0
11 = c
Put in equation (1) , we get
h = ( 0.6 t^2 + 3t + 11 ) cm
Thus, teh height of tree after t years is given by
( 0.6 t^2 + 3t + 11 ) cm.
<span>The logic in the sequence is --> +2, +2, +3, +3, +4, +4, +5, +5, +6, +6 and so on...
So, </span><span>the next number in the sequence would be 24+5 = 29
So, the answer is --> c.29
</span>
Answer:
4
Step-by-step explanation:
8+2=10
10x2=60
60-2^4=4
the value of 2^4 is 56
Answer:
The equation that can be used to determine the maximum height is given as h = 15tan4.76°
Step-by-step explanation:
The question given is lacking an information. Here is the correct question.
"By law, a wheelchair service ramp may be inclined no more than 4.76 degrees. If the base of the ramp begins 15 feet from the base of a public building, which equation could be used to determine the maximum height, h, of the ramp where it reaches the building's entrance"
The whole set up will give us a right angled triangle with the base of the building serving as the adjacent side of the triangle and the height h serving as the opposite side since it is facing the angle 4.76°
The side of the wheelchair service ramp is the hypotenuse.
Given theta = 4.76°
And the base of the building = adjacent = 15feet
We can get the height of the building using the trigonometry identity SOH CAH TOA.
Using TOA
Tan(theta) = opposite/Adjacent
Tan 4.76° = h/15
h = 15tan4.76°
The equation that can be used to determine the maximum height is given as h = 15tan4.76°
