Answer:
(b) The interquartile range of B is greater than the interquartile range of A.
(d) The median of A is the same as the median of B.
Explanation:
Given


So:

Required
Select all true statements
(a) & (d) Median Comparisons


Arrange the data:




--- average of 5th and 6th

Option (d) is correct because both have a median of: 2
(b) & (c) Interquartile Range Comparisons


First, calculate the lower quartile (Q1)
[Odd n]
[Even n]


This means that:


Next, calculate the upper quartile (Q3)
[Odd n]
[Even n]

This means that:

The interquartile range is 
So, we have:


(b) is true because B has a greater IQR than A
(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.
The upper quartile and the interquartile range of A and B are not equal
Answer:
All the offsprings would be heterozygous purple colored flower
Explanation:
Given
Purple color flower is dominant over white color flower
Let the allele for purple color of flower be represented by "P"
and the allele for white color flower be represented by "p"
A pea plant that is homozygous purple-flowered is crossed with a pea plant that is white-flowered.
Genotype of homozygous purple-flower is "PP"
and Genotype of homozygous white-flower is "pp"
Cross between PP and pp produce the following offspring
PP * pp
Pp, Pp , Pp , Pp
All the offsprings would be heterozygous purple colored flower
Answer:
B
Explanation:
Its 23 in mitosis cell division
Answer:
What is a. A; A
Explanation:
Drop 1 struck the surface from direction A, and drop 2 struck the surface from direction A.