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3 years ago

A number increased by 10 is equal to 340 in equation form

Mathematics

1 answer:

siniylev [52]3 years ago

6 0

Answer:

x=330

Step-by-step explanation:

x+10=340

-10

x=330

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What is the following product?

VMariaS [17]

For this case we must find the product of the following expression:

$\sqrt {12} * \sqrt {18}$

We combine using the product rule for radicals:

$\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}$

So, we have:

$\sqrt {12 * 18} =\\\sqrt {216} =$

We rewrite the 216 as $6 * 6 * 6 = 6 ^ 3 = 6 ^ 2 * 6$

$\sqrt {6 ^ 2 * 6} =$

By definition of properties of powers and roots we have:

$\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a$

Then, the expression is:

$6 \sqrt {6}$

Answer:

Option D

6 0

3 years ago

Read 2 more answers

Find the missing number so that it has no solution. __x-8-9x=-4x+8

Nutka1998 [239]

Answer:

The missing number (i.e. the coefficient of x) is 5.

Step-by-step explanation:

5x - 8 - 9x = -4x + 8

-4x - 8 = -4x + 8

-8 ≠ 8

3 0

3 years ago

I’ll mark brainlest:( i need help!

enyata [817]

Answer: Choice A) $3 \sqrt{26}$

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Work Shown:

$\text{The two points are } (x_1,y_1) = (6,7) \text{ and } (x_2,y_2) = (3,-8)\\\\d = \text{Distance between } (x_1,y_1) \text{ and } (x_2,y_2)\\\\d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2} = \text{Distance Formula}\\\\d = \sqrt{(6-3)^2+(7-(-8))^2}\\\\d = \sqrt{(6-3)^2+(7+8)^2}\\\\$

$d = \sqrt{(3)^2+(15)^2}\\\\d = \sqrt{9+225}\\\\d = \sqrt{234}\\\\d = \sqrt{9*26}\\\\d = \sqrt{9}*\sqrt{26}\\\\d = 3\sqrt{26}\\\\$

When going from 234 to 9*26, the idea here is to factor where one factor is the largest perfect square possible. That way we can use the rule $\sqrt{x*y} = \sqrt{x}*\sqrt{y}$ to break up the root and simplify.