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gogolik [260]
4 years ago
9

A number increased by 10 is equal to 340 in equation form

Mathematics
1 answer:
siniylev [52]4 years ago
6 0

Answer:

x=330

Step-by-step explanation:

x+10=340

-10

x=330

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Describe a situation that could be represented with this tape diagram.
Maurinko [17]

Answer:

Pre-Hispanic Philippine literature was actually epics passed on from generation to generation, originally through an oral tradition. However, wealthy families, especially in Mindanao, were able to keep transcribed copies of these epics as family heirloom. One such was the Darangen, an epic of the Maranaos.

8 0
3 years ago
What is the solution to the equation 2/3x-5/6=-5/12x+1/4
vlabodo [156]

Answer: X=13/3

Step-by-step explanation:

1. Multiply Both sides by 12

8x-10=5x+3

2. Collect the like terms, calculate the sum

8x-5x=3+10

3.Divide both sides by 3

3x=13

Answer X=13/3

Alternative Form,

X= 4 1/3, X=4.3

5 0
4 years ago
Wade's grandmother gave him $100 for his birthday. Wade wants to save his money to buy a new MP3 player that cost $275. Each mon
SCORPION-xisa [38]
7 months because after the 100 dollars u add u 25 7 times to get 275
5 0
3 years ago
Read 2 more answers
Hey guys how do you simplify this fully?​
Masja [62]

Answer:

32

Step-by-step explanation:

In 100^1000,

100 can be written as,

100 = 10 x 10 = 10^2

100^1000

= 10^( 2 * 1000 )

= 10^2000

10 can be written as,

10 = 2 x 5

10^2000

= ( 2 x 5 )^2000

Formula : -

( a x b )^n = a^n x b^n

Here,

a = 2

b = 5

n = 2000

( 2 x 5 )^2000 = 2^2000 x 5^2000

[ 2^2005 x 5^2000 ] / 100^1000

= [ 2^2005 x 5^2000 ] / [ 2^2000 x 5^2000 ]

Formula : -

a^m x b^n / a^c x b^d

= a^( m - c ) x b^( n - d )

Here,

a = 2

m = 2005

c = 2000

b = 5

n = d = 2000

[ 2^2005 x 5^2000 ] / [ 2^2000 x 5^2000 ]

= 2^( 2005 - 2000 ) x 5^( 2000 - 2000 )

= 2^5 x 5^0

{ Note : Any number power 0 ( except 0 ) is 1.

That is 0^0 ≠ 1, but 5^0 = 1. }

= 2^5 x 1

= 2^5

= 2 x 2 x 2 x 2 x 2

= 32

5 0
3 years ago
Which of the following expressions are equivalent to 48a^3—75a select all that apply
Vladimir [108]

Answer:

3a(16a^2-25)

3a(4a-5)(4a+5)

Step-by-step explanation:

The equation 48a^3-75a is factorable using GCF and difference of squares.

First, we factor 3a from each term.

3a(16a^2-25)

The term in the parenthesis {16a^2-25) has the form a^2-b^2 = (a-b)(a+b) which factors into two terms where a and b are the squares root of their respective terms.

3a(16a^2-25)\\3a(4a-5)(4a+5)


3 0
3 years ago
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