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3 years ago

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In 1993, funding for a program increased by 0.79 billion dollars from the funding in 1992. In 1994, the increase was 0.49 billio

n dollars over the funding in 1993. For those three years the funding was 11.58 billion dollars. How much was funded in each of these three years?

1 answer:

Tomtit [17]3 years ago

8 0

Hi I'm new wanna be my friend =D!!!!!!!!!!!!!

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Please help asap! really important!!

Alexxandr [17]

Answer:

4th graph

6th graph

3rd graph

Step-by-step explanation:

Linear = y = x + 3

it is 4th graph

when you substitute x = 0 y is 3

and when y = 0 x is -3

Quadratic = y = 3x^2

It is 6th graph

for both positive and negative values of x, y is rapidly increasing

Exponential = y = 3^x

it is 3rd graph

for x = 0 y value is 1 because 3^0 = 1

for positive values of x, y is exponentially rising

for negative values of x it is nearly almost touches zero

6 0

2 years ago

5. Which graph shows a line with the same y-intercept as the graph of 10x-16y=-40?

Aleksandr-060686 [28]

Answer: B

Step-by-step explanation:

8 0

2 years ago

Wane went on a 4-kilometer run he took a break at four third kilometers he took a drink of water at ten third kilometers show Wa

otez555 [7]

Answer:

Given,

The total distance covered = 4 km,

Since, initially he would be in rest,

So, his starting point would be 0.

Now, his first break = $\frac{4}{3}$ km,

Second break = $\frac{10}{3}$ km,

Also, we can write,

$4=\frac{4\times 3}{3}=\frac{12}{3}$

Drawing number line:

Step 1: Draw a line.

Step 2: Make 12 marks in same distance.

Step 3: Starts from 0, then 1/3, 2/3, 3/3 and so on.

Thus, we can show Wayne's bike on a number line as below.

6 0

3 years ago

Somebody help me lol

Lapatulllka [165]

Answer:

c

you subtract the exponents when dividing numbers with the same base

4 0

3 years ago

Determine the projection of w onto u.

irina [24]

Answer:

A.6.2i-4.2 j

Step-by-step explanation:

We are given that

$u=9i-6j$

$v=-3i-2j$

$w=19i+15j$

We have to find the projection of w on to u.

The project of vector a on b

= $\frac{a\cdot b}{\mid b\mid^2}b$

$w.u=(19i+15j)\cdot (9i-6j)=171-90=81$

$\mid u\mid=\sqrt{x^2+y^2}=\sqrt{9^2+(-6)^2}=\sqrt{117}$

Using the formula

The projection of w on to u

$=\frac{u\cdot w}{\mid u\mid^2}(u)=\frac{81}{117}(9i-6j)$

The projection of w on to u=6.2i-4.2j

Hence, option A is true.

4 0

3 years ago

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