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3 years ago

Do you know 3 prime numbers that equal 32

Mathematics

2 answers:

Makovka662 [10]3 years ago

8 0

3 prime numbers that = 32:
23+7+2

Firdavs [7]3 years ago

4 0

17+13+2=32
.........................................

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Select all equations that are true. A. 9 . 21 × 10 3 = 921 B. 9 . 21 × 10 1 = 92 . 1 C. 0 . 921 × 100 = 921 D. 0 . 921 × 10 4 =

olasank [31]

Answer:

Option B
Option D
Option E

Step-by-step explanation:

Option A

9.21 * 10³ = 9,210 ≠ 921

Option A is FALSE.

Option B

9.21 * 10¹ = 92.1

Option B is TRUE.

Option C

0.921 * 100 = 92.1 ≠ 921

Option C is FALSE

Option D

0.921 * 10⁴ = 9,210

Option D is TRUE

Option E

0.0921 * 10² = 9.21

Option E is TRUE

5 0

3 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

brilliants [131]

Answer:

triangle ABD> triangle BDC answer is B

Step-by-step explanation:

reason is because A-D is 5 while B-C is 4.5 the other sides are equal so ABD is larger

8 0

3 years ago

Read 2 more answers

Convert from DMS (degrees, minutes, seconds) to decimal form (degrees)

tino4ka555 [31]

All I remember is: 1° (degree) = 60' (minute) = 3600" (second) and use the given numbers to put on the..... d° m' s"........dd = d + m/60 + s/3600

1) 118°44'15" => 118/1 + 44/60 + 15/3600 = 118.7375

same thing with
2) <span>48°30'36" => 48 + 30/60 + 36/3600 = 48.51</span>

3 0

3 years ago

The mean height of a group of 500 nonsmoking college students is 74 inches and the standard deviation is 5 inches. What is the p

Brrunno [24]

500 (non smokers)÷ 25(random students out of the group)= 20 inches. 20 inches ÷ 74 inches= 3.70

3 0

3 years ago

Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a

cluponka [151]

Answer:

B. Train B

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

$\text{Distance}=\text{Speed*Time}$

$\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}$

$\text{Distance traveled by train A}=90\times 3{\text{ miles}$

$\text{Distance traveled by train A}=270{\text{ miles}$

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

$\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}$

$\text{Distance traveled by train B}=70\times 5 \text{ miles}$

$\text{Distance traveled by train B}=350\text{ miles}$

Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.

5 0

3 years ago