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4 years ago

2 1/2 divided by (-1 3/4)

Mathematics

2 answers:

BlackZzzverrR [31]4 years ago

7 0

Answer:

-1 3/7

Step-by-step explanation:

If your calculator doesn't do this directly, you can convert each of the numbers to an improper fraction and do the fraction division.

2 1/2 = 5/2

-1 3/4 = -7/4

Then the division is ...

(5/2)/(-7/4) = -(10/4)/(7/4) = -10/7 = -1 3/7 . . . . . using same denominators

(5/2)/(-7/4) = -(5/2)(4/7) = -10/7 = -1 3/7 . . . . . . using "invert and multiply"

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<em>Comment on dividing fractions</em>

You can always divide fractions using the "invert and multiply" technique. The quantity inverted is the denominator. That is, dividing by a value is the same as multiplying by the inverse of that value:

(a/b) / (c/d) = (a/b) × (d/c) = (ad)/(bc)

It is often useful to cancel common factors from numerator and denominator before doing the multiplication.

When the two fractions being divided have the same denominator, their quotient is the ratio of their numerators:

(a/b) / (c/b) = a/c

Sometimes, it is easy to adjust the denominators to be the same value, making this method of division the one of choice.

Gekata [30.6K]4 years ago

4 0

Answer:

-1 3/7

Step-by-step explanation:

$-1 \frac{3}{7}$

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Answer:

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3 years ago

what types of problems can be solved using the greatest common factor what types of problems can be solved using the last common

jonny [76]

Answer:

The greatest common factor is the biggest factor that divides two different numbers. For example, the greatest common factor of 6 and 8 is 2. The least common multiple is the smallest number that two numbers share as a multiple. For example, 12 is a the lowest common multiple of 3 and 4.

Step-by-step explanation:

3 0

4 years ago

A manufacturer claims that its drug test will detect steroid use (that is, show positive for an athlete who uses steroids) 95% o

amid [387]

Answer:

The probability tree is;

0.95 $(+)$

$(S)$

0.1 0.05 $(-)$

[ P ]

0.9 0.15 $(+)$

$(S_{no})$

0.85 $(-)$

Step-by-step explanation:

Given the data in the question;

10% of the rugby team members use steroids

so Probability of using steroid; P( use steroid ) = 10% = 0.10

Probability of not using steroid; P( no steroid use ) = 1 - 0.10 = 0.90

Since the test show positive for an athlete who uses steroids, 95% of the time.

Probability of using steroids and testing positive = 95% = 0.95

Probability of using steroids and testing Negative = 1 - 0.95 = 0.05

Also from the test, 15% of all steroid-free individuals also test positive.

Probability of not using steroids and testing positive = 15% = 0.15

Probability of not using steroids and testing negative = 1 - 0.15 = 0.85

To set up the probability tree, Let;

$(S)$ represent steroid use

$(S_{no})$ represent no steroid use

$(+)$ represent test positive

$(-)$ represent test negative

so we have;

0.95 $(+)$

$(S)$

0.1 0.05 $(-)$

[ P ]

0.9 0.15 $(+)$

$(S_{no})$

0.85 $(-)$

7 0

3 years ago

Mitchell's family is slow cooking 2 3/4 pounds of meat. The recipe says to cook the meat 1 1/2 nours per pound,

nlexa [21]

Answer:

Step-by-step explanation:

Multiply the 1.5 hours per pound by 2.75 pounds and we get 4.125 hours or 4 1/8

6 0

4 years ago

Read 2 more answers

The 6-lb particle is subjected to the action of its weight and forces F1 = 52i + 6j - 2tk6 lb, F2 = 5t 2 i - 4tj - 1k6 lb, and F

olga2289 [7]

Answer:

r=294.9m

Step-by-step explanation:

The forces on the particle are

$W=mg\hat{j}\\F_{1}=52\hat{i}+6\hat{j}-2t\hat{k}\\F_{2}=5t^{2}\hat{i}-4t\hat{j}-1\hat{k}\\F_{3}=(5-2t)\hat{i}$

Now , we sum all these forces to get the net force

$F_{T}=W+F_{1}+F_{2}+F_{3}\\F_{T}=(52+5t^{2}+5-2t)\hat{i}+((6+6-4t)\hat{j}+(-2t-1)\hat{k}\\F_{T}=(57-2t+5t^{2})\hat{i}+(12-4t)\hat{j}+(-2t-1)\hat{k}\\$

we can use the fact F=m*a and integrate the acceleration

$a(t)=\frac{1}{m}F(t)\\\\v(t)=\int a(t)dt=\frac{1}{m}\int{F_{T}}dt\\\\v(t)=\frac{1}{m}[(57t-t^{2}+\frac{5}{3}t^{3})\hat{i}+(12t-2t^{2})\hat{j}+(-t^{2}-t)\hat{k}]\\\\r(t)=\int v(t)dt=\frac{1}{m}[(\frac{57}{2}t^{2}-\frac{1}{3}t^{3}}+\frac{5}{4}t^{4})\hat{i}+(6t^{2}-\frac{2}{3}t^{3})\hat{j}+(-\frac{1}{3}t^{3}-\frac{1}{2}t^{2})]$

and we evaluate in r(2) an we take the norm to obtain the distance

$r(2)=\frac{1}{m}[\frac{394}{3}\hat{i}+\frac{56}{3}\hat{j}-\frac{14}{3}\hat{k}]\\|r(2)|=\frac{1}{m}\sqrt{[(\frac{394}{3})^{2}+(\frac{56}{3})^{2}+(\frac{14}{3})^{2}]}\\|r(2)|=\frac{132.73}{0.45}=294.9m$

I hope this is useful for you

regards

8 0

4 years ago