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drek231 [11]
4 years ago
11

Peter attends 6 dance lessons each week all year long. A year has 52 weeks. Peter missed 5 dance lesson while sick. How many dan

ce lessons did Peter attend durning the years?
Mathematics
2 answers:
nexus9112 [7]4 years ago
5 0
307 dance classes, I hope this helps you
Oliga [24]4 years ago
4 0
The answer is 307 dance classes! I hope this helps and if not I am very sorry
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What grades are considered good?
Dahasolnce [82]

Answer:

Depends who you are and what your standard grades are...

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Work out the surface area of this solid prism.
zhannawk [14.2K]
THE SURFACE AREA IS 3220CM^2
3 0
2 years ago
Find the area of a regular polygon
Law Incorporation [45]

Answer: Area of the polygon is 43.31 cm^2 t

Step-by-step explanation:

The polygon show in the diagram is a hexagon. It has six sides, since it is a regular hexagon, all the six sides are equal.

From the information given, the apotherm = 5√3

The apotherm is the perpendicular distance from the center of one side of the polygon to the center of the polygon. To determine the area of the polygon,

Area of polygon

=area = a^2n ×tan 180/n

Area = (5√3)^2 tan(180/6)

Area = 5^2×(√3)^2 × tan30

Area = 25×3×0.5774

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7 0
3 years ago
Harry drove 2 hours on the freeway then decreased his speed by 20mph and drove 6 more hours. total trip was 352 what was his spe
poizon [28]
Recall your d = rt, distance = rate * time

we know the total trip was 352miles, so, let's say he was going for the first 2hrs at "r" speed, he went "d" miles, then he slowed down to "r - 20" and went 6 more hours, since the total trip is 352 miles, the 6hrs take the slack from 352 - d, and that's how many miles he covered on those 6hours

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{before slowing}&d&r&2\\
\textit{after slowing}&352-d&r-20&6
\end{array}
\\\\\\

\begin{cases}
\boxed{d}=2r\\
352-d=(r-20)6\\
----------\\
352-\boxed{2r}=(r-20)6
\end{cases}

solve for "r".
7 0
4 years ago
On the unit circle, an angle terminates at the coordinate (x,y). What is the relationship between the x and y components of the
Ivahew [28]

The unit circle is represented below:

As can be observed in the figure above, for an angle (t), the relation between the trigonometric functions and x and y components is:

x = cos(t)

y = sen(t)

x is positive in the first and in the fourth quadrant. Thus, cos (t) will be positive for angles in the first and fourth quadrant.

y is positive in the first and in the second quadrant. Thus, sin (t) will be positive for angles in the first and second quadrant.

6 0
2 years ago
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