Complete question is;
Suppose that a dimension x and the area A = 2x² of a shape are differentiable functions of t. Write an equation that relates dA/dt to dx/dt.
Answer:
Step-by-step explanation:
Since A = 2x²
Let's differentiate both sides with respect to x.
dA/dx = 4x
Now, we want to find the relationship between dA/dt and dx/dt
dA/dt can be expressed as;
(dA/dt) = (dA/dx) × (dx/dt)
Thus;
dA/dt = 4x(dx/dt)
Thus, the equation that relates dA/dt to dx/dt is;
dA/dt = 4x(dx/dt)
Answer:
D. 5 +6k/n
Step-by-step explanation:
The width of the interval is (5 -2) = 3. The width of one of n parts of it will be ...
3/n
Then the difference between the left end point of the interval and the value of x at the right end of the k-th rectangle will be ...
k·(3/n) = 3k/n
So, the value of x at that point is that difference added to the interval's left end:
2 + 3k/n
The value of the function for this value of x is ...
f(2 +3k/n) = 2(2 +3k/n) +1 = (4 +6k/n) +1
= 5 +6k/n
Answer: stephen was correct
Step-by-step explanation:
i just did it now
Where is the graph ??
Please provide the graph so that we can answer your questions ....
Answer:
72 hectares
Step-by-step explanation:
The dimensions of the rectangle on the ground will be 20,000 times the dimensions shown in the drawing:
20,000×3 cm = 60,000 cm = 600 m
20,000×6 cm = 120,000 cm = 1200 m
The area of the land is ...
A = LW = (1200 m)(600 m) = 720,000 m²
1 hectare is 10,000 m², so this is ...
720,000 m² × (1 ha)/(10,000 m²) = 72 ha
The area of the plot is 72 hectares.
