We know angle P is 90 degrees because of Thales Theorem, and angle N is 60 degrees. Because the angles in a triangle have to add up to 180 degrees, angle PMN has to be 30 degrees.
Angle QMO is half of angle PMN, so it's 15 degrees. Angle MQO is equal to angle QMO because the radii make Triangle OQM isosceles, so angle MQO is 15 degrees.
Answer:
$8
Step-by-step explanation:
20% (= 0.20) is deducted from $40.40 * 0.20 = $8.
Answer:
1 : 15
2: 12
3: 52
4: 27.3
Step-by-step explanation:
For #1:
if line m and n are perpendicular then they will create right angles
Right angles have a measure of 90 degrees
That being said we can find the measure of the missing angle by subtracting the measure of the known angle (75) from 90
so k = 90 - 75
90 - 75 = 15
Hence k = 15.
For #3 ( very similar to #1, only difference is the values of the angles )
so R = 90 - 38
90 - 38 = 52
Hence, R = 52
For #2 and #4
Complementary angles have a sum of 90°
So like the previous questions we can find the measure of the missing angle by subtract the measure of the given angle from 90
∠V = 90 - 78
90 - 78 = 12
Hence ∠V = 12
∠Y = 90 - 62.7
90 - 62.7 = 27.3
Hence ∠Y = 27.3
Perimeter of rectangle:
P = 2(L + W)
P = 250 (given)
L = 3W - 35 (given)
250 = 2(3W -35 + W) ↔ 125 = 4W - 35
4W = 125 +35 =160 And W = 40 ft
And L = 3x40 - 35 = 85 ft
