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scoray [572]
3 years ago
12

The interior angles of a triangle have measures (2x - 5), (4– 1), and 30°

Mathematics
1 answer:
const2013 [10]3 years ago
8 0

Answer: x=26

Step-by-step explanation:

1. Write the equation 2x-5+4x-1+30=180 because all triangle angles add up to 180°

2. Simplify the equation by combining like terms. Write the equation as 6x+24=180

3. Subtract 24 from both sides. Write the equation as 6x=156.

4. Divide 156/6 and get 26. That is your answer (x=26).

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Answer:

b < 16.5

Step-by-step explanation:

b - 9.5 + 9.5 < 7 + 9.5

b <  16.5

hope this helped :D

5 0
3 years ago
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ELEN [110]

9514 1404 393

Answer:

  a) BE = 5; DE = 6; EF = 4

  b) ∠EFC ≅ ∠DA.F ≅ ∠BDE  or  <em>b = e = f = i</em>

Step-by-step explanation:

Each short segment is the same length as the marked one it is parallel to.

  E is the midpoint of BC, so BE = EC = 5.

  ADEF is a parallelogram, so DE = A.F = 6.

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     EF = AD = 4

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As we have noted, AB║EF and DE║A.F, so corresponding angles and alternate interior angles are congruent. <em>b = e = f = i</em>

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3 years ago
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blsea [12.9K]

Answer:

<h2>20</h2>

Step-by-step explanation:

4a+7b+3a-2b\qquad\text{combine like terms}\\\\=(4a+3a)+(7b-2b)\\\\=7a+5b\qquad\text{put a = 5 and b = -3 to the expression}\\\\7(5)+5(-3)=35-15=20

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Step-by-step explanation:

We have been given that AE=BE and \angle1\cong \angle2.

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We can see in triangles CEA and DEF that two angles and included sides are congruent.

\angle 1\cong \angle 2

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Therefore, \Delta CEA\cong \Delta DEB by ASA postulate.

Since corresponding parts of congruent triangles are congruent, therefore CE must be congruent to DE.

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Answer:

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Step-by-step explanation:

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