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myrzilka [38]
4 years ago
13

Each night Ann and her family empty their pockets, purses, and wallets and place all of the pennies, nickels, dimes, and quarter

s in a large container. Ann helps her father count the money. If there are 145 pennies, 42 dimes, & 12 quarters, how much money did she count?
Mathematics
1 answer:
Sedaia [141]4 years ago
8 0
The easiest way to solve this is to take the amount of each coin and multiply it by its value. Afterwards add each total together to determine the amount of money that Ann has.

145 pennies X $0.01 = $1.45

42 dimes X $0.10 = $4.20

12 quarters X $0.25 = $3.00

$1.45 + $4.20 + $3.00 = $8.65

Therefore Ann has $8.65
You might be interested in
Emily Elizabeth has $1.50 in dimes and nickels. She has 22 coins in all. How many nickels does she have?
Marat540 [252]

Answer:

14

Step-by-step explanation:

We can set up the following system of equations:

\begin{cases}10d+5n=150\\d+n=22\\\end{cases}, where d is the number of dimes she has and n is the number of nickels she has.

Multiplying the second equation by -5 and adding both equations lets us isolate and solve for d:

10d+5n+(-5(d+n))=150+(-5(22)),\\5d=40,\\d=8

Plugging d=8 into any of the two equations will let us solve for n:

8+n=22,\\n=\fbox{$14$}.

Therefore, she has 14 nickels.

6 0
3 years ago
To prepare a batch of cookies a factory uses 4/5 barrels of oatmeal in each batch. The factory used 4 4/5 barrels of oatmeal on
babymother [125]

Answer:

Step-by-step explanation:

4 4/5= 24/5  24/5\4/5=6/5= 1/15

6 0
4 years ago
Anita Is filling a small pool for her kids. Currently, there are 60 gallons of water in the pool and she is filling he pool at a
Finger [1]

Answer:

M/140 = 50/60

Step-by-step explanation:

Since the total is 200 it will be the denominator but we already have 60 gallons so we do 200-60=140

the ratio is 50 per 60

7 0
3 years ago
In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
3 years ago
I WILL MARK BRAINLIST, HELP PLEASE
Rudik [331]

Answer:

 t = 204    

Step-by-step explanation:

Let t = initial number of trees

 

"remove 5 trees at the start of the season"  means

    (t    - 5)     remain

 

"each remaining tree made 210 oranges for a total of 41,790 oranges"    means

        ( t   - 5)           *        210                  = 41790

 

Now, you can solve for t:

       (t-5)(210) = 41790                     [just re-writing]

       210t - 1050 = 41790                    [distribute]

       210t = 42840                            [add 1050 to each side]

         t = 204                                  [divide each side by 210]

 

There were initially 204 trees.  After 5 were removed, the remaining 199 produced 210 oranges each for a total of 199*210 = 41790 oranges.

8 0
3 years ago
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