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3 years ago

What is a naked number?

Mathematics

2 answers:

Sever21 [200]3 years ago

8 0

Answer:

A number without units

Step-by-step explanation:

snow_lady [41]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

The question that follows this graph is:

azamat

Answer:

S'(5,-1), M'(1,-3)

Step-by-step explanation:

So, if the rotation is clockwise, the formula is (x,y)--->(-x,-y).

The original points are, (-1,3) and (-5,1).

Using the formula,

(-1,3) ----> (1,-3)

(-5,1) ----> (5,-1)

For the question in the image, the reflection over the x-axis is..

S'(-5,1) ---> (-5,-1)

M'(1,-3) ---> (-1,-3)

6 0

4 years ago

2 more and I’m done thank y’all so much sorry I’m dumb and in 8th grade LOL

kotegsom [21]

9. -5(4+6r)

-20-30r

-20-30(4)=-20-120=-140

10. -9-n/3

-9-9/3=-9-3=-12

answers: -140, -12

7 0

3 years ago

Read 2 more answers

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.