It is a linear equation so there can be 1 solution, 0 solutions, or infinite solutions
4(x-5)=4x-24
distribute
4x -20 = 4x-24
subtract 4x from each side
-20 = -24
no solutions
Answer: look at the picture
Step-by-step explanation: Hope this help :D
Answer:
Step-by-step explanation:
The set {1,2,3,4,5,6} has a total of 6! permutations
a. Of those 6! permutations, 5!=120 begin with 1. So first 120 numbers would contain 1 as the unit digit.
b. The next 120, including the 124th, would begin with '2'
c. Then of the 5! numbers beginning with 2, there are 4!=24 including the 124th number, which have the second digit =1
d. Of these 4! permutations beginning with 21, there are 3!=6 including the 124th permutation which have third digit 3
e. Among these 3! permutations beginning with 213, there are 2 numbers with the fourth digit =4 (121th & 122th), 2 with fourth digit 5 (numbers 123 & 124) and 2 with fourth digit 6 (numbers 125 and 126).
Lastly, of the 2! permutations beginning with 2135, there is one with 5th digit 4 (number 123) and one with 5 digit 6 (number 124).
∴ The 124th number is 213564
Similarly reversing the above procedure we can determine the position of 321546 to be 267th on the list.
Answer:
B. a = 4, b = -8, c = -3
Step-by-step explanation:
The quadratic equation given is:
The general form of a quadratic equation is given as:
Let us put the given equation in this form and then compare with the general form of the quadratic equation.
Therefore, by comparing:
a = 4
b = -8
c = -3
The correct option is B
