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3 years ago

7

four survivors in a lifeboat have enough water for 12 days. calculate how long the water would have lasted if there had 6 people

on the lifeboat.

1 answer:

algol [13]3 years ago

3 0

32 jnshxvs 34522gvvbkkmabsbfi

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Add 1/4 and 5/8 by using the giant one to create a common denominator <br> thanks

Sedbober [7]

Answer:

7/8

Step-by-step explanation:

1/4×2=2/8....2/8+5/8=7/8

3 0

3 years ago

if you could JUST TELL ME HOW TO SOLVE IT that would be great. Or you could send a pic of your paper. thanks

fgiga [73]

Lets p = salesman's commission as percent
15,200 * p = 912
p = 912/ 15,200
p = 0.06
p = 6%

answer
6%

3 0

3 years ago

Hmm who is smart enough for this :)

Goryan [66]

Answer:

1

$-\frac{9}{15}$

-0.7

Step-by-step explanation:

Both $-\frac{9}{15}$ and -0.7 are negative so therefore, 1 is the greatest

$-\frac{9}{15}$ is -0.6 which is greater than -0.7 so it's the 2nd greatest

and -0.7 is the least

7 0

3 years ago

Read 2 more answers

Jason has 5 shirts for every 2 pairs of pants. His brother John has 7 shirts for every 3 pairs of pants. Compare the ratio by co

postnew [5]

Answer:

john has a greater ratio of shirts to pants

Step-by-step explanation:

jason- 5:2

table:

shirt :5 10 15 20 25 30 35 40 45

pants:2 4 6 8 10 12 14 16 18 20

john-7:3

table:

shirts:7 14 21 28 35 42 49 56 63

pants:3 6 9 1 2 15 18 21 24 27

4 0

2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

OLga [1]

y^2(y^2+6) + 6(y^2+6)

(y^2+6)^2

4 0

3 years ago