Newton stated 3 laws that rules moving bodies:
First law - an object remains in its state (resting or moving at constant speed) unless acted upon a force
Second law - the force (F) of an object is equal to its mass (m) multiplied by its acceleration (a); F = m x a
Third law - when an object exerts a force upon another, the second object exerts a force that is equal in magnitude and opposite in direction
So, according to the First Law of Motion, the metor moving through outer space will continues its motion until an outside force acts upon it
Explanation:
The force on the passenger will be F = ma
Here, m does not change, but a is the variable.
If the cars slows down very fast, the acceleration will be higher, and thus the force will be higher.
If the acceleration is lower, the force will be lower as well, which would be the most desirable scenario for the passenger.
Burning of gases is one the example of chemical change
Concept: According to Ohm's Law, the flow of electric current through a conductor is directly proportional to the potential difference across it, provided physical conditions (like temperature, pressure, volume etc.) remains same.
v = ir
or, r = v / i
Here, current (i) is measured by Ammeter which should be connected in series of any electrical circuit.
voltage (v) is measured by Voltmeter which should be connected parallel to the external resistance (r).
In the given experiment, the first arrangement of the circuit will show the smallest error because the voltmeter is connected exactly parallel to the external resistance.
In the second arrangement, the voltmeter is connected across external resistance (r) and Ammeter (A) and in this case, the voltmeter will not measure the exact potential drop across the external resistance (r). So, there would be more error.
Let car A's starting position be the origin, so that its position at time <em>t</em> is
A: <em>x</em> = (40 m/s) <em>t</em>
and car B has position at time <em>t</em> of
B: <em>x</em> = 100 m - (60 m/s) <em>t</em>
<em />
They meet when their positions are equal:
(40 m/s) <em>t</em> = 100 m - (60 m/s) <em>t</em>
(100 m/s) <em>t</em> = 100 m
<em>t</em> = (100 m) / (100 m/s) = 1 s
so the cars meet 1 second after they start moving.
They are 100 m apart when the difference in their positions is equal to 100 m:
(40 m/s) <em>t</em> - (100 m - (60 m/s) <em>t</em>) = 100 m
(subtract car B's position from car A's position because we take car A's direction to be positive)
(100 m/s) <em>t</em> = 200 m
<em>t</em> = (200 m) / (100 m/s) = 2 s
so the cars are 100 m apart after 2 seconds.
