The charge of the object must be 
Answer: Option C
<u>Explanation:</u>
Suppose an electric charge can be represented by the symbol Q. This electric charge generates an electric field; Because Q is the source of the electric field, we call this as source charge. The electric field strength of the source charge can be measured with any other charge anywhere in the area. The test charges used to test the field strength.
Its quantity indicated by the symbol q. In the electric field, q exerts an electric, either attractive or repulsive force. As usual, this force is indicated by the symbol F. The electric field’s magnitude is simply defined as the force per charge (q) on Q.

Here, given E = 4500 N/C and F = 0.05 N.
We need to find charge of the object (q)
By substituting the given values, we get

Answer:
360 ÷ 4 = 90
Example
A 360° circle is cut into 4 peaces in the form of + or × . It's one side is called 90°
The direction of the electric field would be south.
qE/m = 115
<span> E = 115*m/q </span>
<span> = 115 * 9.1 * 10^(-31) / 1.67*10^(-19) </span>
<span> = 762.87 * 10^(-12) </span>
<span> = 6.27 x 10^-10 N/C
</span>
Hope this answers the question. Have a nice day. Feel free to ask more questions.
It is important to look at all the information's that are given in the question very closely. Let us write them write first.
Radius of the spa = <span>5/√2-1 feet
Now
Perimeter of the circle = </span><span>2πr
= 2</span>π (5/√2-1)
= <span>π(5/(√2-1)*(√2+1)/(√2+1) </span>
<span> = 2π(5/(√2+1))/(2-1) </span>
<span> = 10π(√2+1)
I hope that the procedure is clear enough for you to understand.</span>