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4 years ago

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A car and a heavy truck roll down a hill and reach the bottom at the same speed. Compared with the momentum of the truck, the mo

mentum of the car is
A. less.B. the same.C. more.D. None of the above.

1 answer:

RoseWind [281]4 years ago

3 0

Answer:

A. less

Explanation:

The momentum of an object is directly proportional to it mass and velocity. It is the product of mass and velocity of the object. Given as

$Momentum (p) = Mass (m) \times Velocity (v)$

So the momentum of car,

$p_{c} = m_{c}\times v_{c}$

Momentum of truck,

$p_{t} = m_{t}\times v_{t}$

We know that, mass of car is less than that of truck and velocity of the two are same. It is implied that, momentum of car will be less than that of truck.

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Your dog is running around the grass in your backyard. He undergoes successive displacements, 3.60 m south, 8.46 m northeast, an

Eduardwww [97]

First, we resolve the northeast displacement into its north and east components. The angle from the positive x-axis of a northeast displacement is 45 degrees. Thus:
North = 8.46sin(45) = 5.98 m
East = 8.46cos(45) = 5.98 m

North displacement = 5.98 - 3.6 = 2.38 m
West displacement = 15.6 - 5.98 = 9.62

Magnitude = √(2.38² + 9.62²)
Magnitude = 9.91 m

Direction:
tan∅ = 2.38 / 9.62
∅ = 13.9° north from east

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3 years ago

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Given the scenario: A 45 kg. object is being pushed north with a force of 8N, and at the same time, it is been pushed east with

sveta [45]

Answer:

10 N, $53.1^{\circ}$ north-east

Explanation:

The two forces applied on the object are perpendicular to each other, so we can find the magnitude of their resultant by using the Pythagorean theorem:

$R=\sqrt{(6 N)^2 + (8 N)^2}=10 N$

The direction of the force instead is given by

$\theta = tan^{-1} (\frac{F_n}{F_e})$

where F_n is the force pointing north, and F_e is the force pointing east, and the angle is measured with respect to the east direction. Substituting,

$\theta=tan^{-1} (\frac{8 N}{6 N})=tan^{-1} (1.333)=53.1^{\circ}$

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3 years ago

Why do naturalists suggest that we plant more trees?

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The answer is so we have more oxygen and because loggers are cutting down more trees every day and the more they cut the less air we have

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4 years ago

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A racing car whose mass is 1.2 X 10^3 kg is travelling at 8.9 m/s. It stops with a constant deceleration in a distance of 1.8X10

Alexeev081 [22]

given that initial speed of the car is

$v_i = 8.9 m/s$

now after travelling the distance d = 1.8 * 10^1 m the car will stop

so here we can use kinematics to find the acceleration of car

$v_f^2 - v_i^2 = 2 a d$

$0 - 8.9^2 = 2 a d$

here we have

$- 79.21 = 2*(18)*a$

$a = -2.2 m/s^2$

net force applied due to brakes of car is given by Newton's II law

$F = ma$

here we have

mass = 1.2 * 10^3 kg

$F_{net} = 1.2 * 10^3 * 2.2$

$F_{net} = 2.64 * 10^3 N$

now we can say

$F_{net} = F_1 + F_2$

$2.64 * 10^3 = 1.8 * 10^3 + F_2$

$F_2 = 8.4 * 10^2 N$

So the force applied due to brakes is given as above

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3 years ago

You have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 10-5 T). I

saul85 [17]

Answer:

$I = 0.03637 A$

Explanation:

The given data in the question is

Magnetic field : $B = 5.0 \times 10^{-5} T$

Turns : $N = 350$

Length : $L = 32 cm = 0.32 m$

So, number of turns per unit length :

$n=\frac{N}{L}$

$n=\frac{350\: turns}{0.32 m}$

$n=1093.75 \: turns \: per \: meter$

If current is I , then magnetic field is given by

$B = \mu_{0} \times n \times I$

Also,

$I = \frac{B}{\mu_{0} \times n}$

Insert the values

$I = \frac{5.0 \times 10^{-5}}{4 \pi \times 10^{-7} \times 1093.75} A$

$I = 0.03637 A$

The current will be $I = 0.03637 A$

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4 years ago